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\[y^2-4y=12 \]

subtract 12 both sides

yep... you get y=6 or -2

you figure out what numbers add to -4 and multiply to negative 12

isn't \[y^2-4y-12=0\]

^ yes that's right...

thanks Luis and Mad

:) If you have any questions.. be sure to ask

KK I think I got it over control for now

Hi Luis can you help step by step

If that's alright with you

I will check khan and my notes I guess I willl be on later