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Solve this equation I like to solve this type of questions guildlines

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\[y^2-4y=12 \]
subtract 12 both sides
yep... you get y=6 or -2

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Other answers:

you figure out what numbers add to -4 and multiply to negative 12
isn't \[y^2-4y-12=0\]
^ yes that's right...
thanks Luis and Mad
:) If you have any questions.. be sure to ask
KK I think I got it over control for now
  • phi
Khan has a whole series of videos on quadratics Lots of stuff to learn.
Hi Luis can you help step by step
If that's alright with you
I will check khan and my notes I guess I willl be on later

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