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sasogeek

  • 4 years ago

A solid weighs W1 in air, W2 when fully immersed in water, and W3 when fully immersed in another liquid. The relative density of the liquid is A. W1/(W2-W3) B. W1/(W1-W2) C. (W1-W3)/(W1-W2) D(W1-W2)/(W1-W3) I'm thinking the answer is C but I'm not quite sure... relative density is density of substance divided by density of water... A and B are eliminated since we're looking for relative density of the liquid. and with C and D, C is the one with W2 in the denominator... :/ what's the right answer?

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  1. JamesJ
    • 4 years ago
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    Write down the equation of the forces acting on the mass in water in terms of the objects mass, volume and and density of water; and the variables W1 and W2 Then write down the equation for the section situation in terms of the same variables, except W3 for W2.

  2. JamesJ
    • 4 years ago
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    Then you want to find the expression for \[ \frac{\rho_{liquid}}{\rho_{water}} \]

  3. sasogeek
    • 4 years ago
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    I'll try that, thanks

  4. JamesJ
    • 4 years ago
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    (and in second situation density of liquid for density of water, obviously)

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