## sasogeek 3 years ago A solid weighs W1 in air, W2 when fully immersed in water, and W3 when fully immersed in another liquid. The relative density of the liquid is A. W1/(W2-W3) B. W1/(W1-W2) C. (W1-W3)/(W1-W2) D(W1-W2)/(W1-W3) I'm thinking the answer is C but I'm not quite sure... relative density is density of substance divided by density of water... A and B are eliminated since we're looking for relative density of the liquid. and with C and D, C is the one with W2 in the denominator... :/ what's the right answer?

1. JamesJ

Write down the equation of the forces acting on the mass in water in terms of the objects mass, volume and and density of water; and the variables W1 and W2 Then write down the equation for the section situation in terms of the same variables, except W3 for W2.

2. JamesJ

Then you want to find the expression for $\frac{\rho_{liquid}}{\rho_{water}}$

3. sasogeek

I'll try that, thanks

4. JamesJ

(and in second situation density of liquid for density of water, obviously)