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Lyla.maskeen

  • 4 years ago

A sled with rider having a combined mass of 110 kg travels over the perfectly smooth icy hill shown in the accompanying figure. http://session.masteringphysics.com/problemAsset/1266926/1/1027475.jpg How far does the sled land from the foot of the cliff?

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  1. shubham
    • 4 years ago
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    Break the problem in 2 parts, 1) find the velocity with which sled reaches the top of clif, and 2) calculating how far does it land. 1) As surface is perfectly smooth, i.e there isn't any dissipative force. Which means you can apply law of energy coonservation. K.E(i) + P.E(i) = K.E(f) + P.E(f) [i- initial, f-final] 1/2*110*22.5^2 + 0 = K.E(f) + 110*9.8*11.0 K.E(f) = ?

  2. shubham
    • 4 years ago
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    So, Lyla.maskeen if you understood the solution till now... should I proceed? any question...

  3. shubham
    • 4 years ago
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    Now, knowing K.E(f) at top of the cliff, you can calculate velocity. Its a case of horizontal projection, multiplying velocity with time of flight will give you your answer. Time of flight = sqrt. ( 2*h/g) = sqrt ( 2*11/9.8) [ using s= ut + 1/2*at^2]

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