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anonymous
 4 years ago
A sled with rider having a combined mass of 110 kg travels over the perfectly smooth icy hill shown in the accompanying figure.
http://session.masteringphysics.com/problemAsset/1266926/1/1027475.jpg
How far does the sled land from the foot of the cliff?
anonymous
 4 years ago
A sled with rider having a combined mass of 110 kg travels over the perfectly smooth icy hill shown in the accompanying figure. http://session.masteringphysics.com/problemAsset/1266926/1/1027475.jpg How far does the sled land from the foot of the cliff?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Break the problem in 2 parts, 1) find the velocity with which sled reaches the top of clif, and 2) calculating how far does it land. 1) As surface is perfectly smooth, i.e there isn't any dissipative force. Which means you can apply law of energy coonservation. K.E(i) + P.E(i) = K.E(f) + P.E(f) [i initial, ffinal] 1/2*110*22.5^2 + 0 = K.E(f) + 110*9.8*11.0 K.E(f) = ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, Lyla.maskeen if you understood the solution till now... should I proceed? any question...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now, knowing K.E(f) at top of the cliff, you can calculate velocity. Its a case of horizontal projection, multiplying velocity with time of flight will give you your answer. Time of flight = sqrt. ( 2*h/g) = sqrt ( 2*11/9.8) [ using s= ut + 1/2*at^2]
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