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VenomGhost

How can you solve a supernode problem like this? The values are: V=5V, I=3A, R1=3ohms, R2=5ohms You have to use the node method and e2 --> Ground (you have a Supernode too)

  • 2 years ago
  • 2 years ago

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  1. VenomGhost
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    Here it's the image of the circuit, You have to obtain e3, I didn't but like a blind guess I need som insight not just good luck xD thanks in advance any help will be apreciated

    • 2 years ago
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  2. Tweedle_Dee
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    First thing I did was redraw it so that the e2 GND point is on the bottom because my brain works that way. So then create the first equation using currents leaving the node(s):

    • 2 years ago
  3. Tweedle_Dee
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    (Having some trouble with the equation editor)

    • 2 years ago
  4. Tweedle_Dee
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    e1/3 + e3/5 + 3A = 0 e1 -e3 = 5V 2 equations, 2 unknowns

    • 2 years ago
  5. VenomGhost
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    no no @Tweedle_Dee that's the idea not redraw! solve it as it is :) that's where the problem lies

    • 2 years ago
  6. Tweedle_Dee
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    Redrawing doesn't change the circuit, it just changes the way you look at it. My equations still apply.

    • 2 years ago
  7. Tweedle_Dee
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    Sorry, I didn't have time to draw it before. This is what I meant by redrawing - just flipping it upside down. Nothing has changed except your perspective. |dw:1331085763933:dw|

    • 2 years ago
  8. VenomGhost
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    ahhhhhhhhhhhhhhh :) well then I'll take a look later on (sleepy ) but if it helps me you got oyur medal :) thank you and good night

    • 2 years ago
  9. VenomGhost
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    Thanks man you're right I finally solved it :)

    • 2 years ago
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