Here's the question you clicked on:
VenomGhost
How can you solve a supernode problem like this? The values are: V=5V, I=3A, R1=3ohms, R2=5ohms You have to use the node method and e2 --> Ground (you have a Supernode too)
Here it's the image of the circuit, You have to obtain e3, I didn't but like a blind guess I need som insight not just good luck xD thanks in advance any help will be apreciated
First thing I did was redraw it so that the e2 GND point is on the bottom because my brain works that way. So then create the first equation using currents leaving the node(s):
(Having some trouble with the equation editor)
e1/3 + e3/5 + 3A = 0 e1 -e3 = 5V 2 equations, 2 unknowns
no no @Tweedle_Dee that's the idea not redraw! solve it as it is :) that's where the problem lies
Redrawing doesn't change the circuit, it just changes the way you look at it. My equations still apply.
Sorry, I didn't have time to draw it before. This is what I meant by redrawing - just flipping it upside down. Nothing has changed except your perspective. |dw:1331085763933:dw|
ahhhhhhhhhhhhhhh :) well then I'll take a look later on (sleepy ) but if it helps me you got oyur medal :) thank you and good night
Thanks man you're right I finally solved it :)