Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

joshua.yeah.

  • 4 years ago

y^2+36x+8y-92 = 0 what are the intercepts of this equation in parabola?

  • This Question is Closed
  1. Callisto
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    put x=0 , y^2+8y-92 = 0 , y= 6.39 or y = -14.39 <-y-int put y=0, 36x-92 = 0 , x=2.556 <- x-int

  2. moongazer
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    parabola has no intercepts. :)

  3. joshua.yeah.
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    im looking for the interceptS, so ill just made it positive negative? and transform it into the standard eq.

  4. joshua.yeah.
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wow.didnt knew that. hehe thanks for the info

  5. moongazer
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    intercepts are just for ellipse and hyperbola.

  6. Callisto
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i thought you're asking the x/y axes int, sorry :(

  7. joshua.yeah.
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its ok. thanks by the way :))

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy