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joshua.yeah.

  • 2 years ago

y^2+36x+8y-92 = 0 what are the intercepts of this equation in parabola?

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  1. Callisto
    • 2 years ago
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    put x=0 , y^2+8y-92 = 0 , y= 6.39 or y = -14.39 <-y-int put y=0, 36x-92 = 0 , x=2.556 <- x-int

  2. moongazer
    • 2 years ago
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    parabola has no intercepts. :)

  3. joshua.yeah.
    • 2 years ago
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    im looking for the interceptS, so ill just made it positive negative? and transform it into the standard eq.

  4. joshua.yeah.
    • 2 years ago
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    wow.didnt knew that. hehe thanks for the info

  5. moongazer
    • 2 years ago
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    intercepts are just for ellipse and hyperbola.

  6. Callisto
    • 2 years ago
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    i thought you're asking the x/y axes int, sorry :(

  7. joshua.yeah.
    • 2 years ago
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    its ok. thanks by the way :))

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