Here's the question you clicked on:
joshua.yeah.
y^2+36x+8y-92 = 0 what are the intercepts of this equation in parabola?
put x=0 , y^2+8y-92 = 0 , y= 6.39 or y = -14.39 <-y-int put y=0, 36x-92 = 0 , x=2.556 <- x-int
parabola has no intercepts. :)
im looking for the interceptS, so ill just made it positive negative? and transform it into the standard eq.
wow.didnt knew that. hehe thanks for the info
intercepts are just for ellipse and hyperbola.
i thought you're asking the x/y axes int, sorry :(
its ok. thanks by the way :))