Please help me with this system. I'm not getting the y or z. -x+2y+z=2 3x+y+z=12 x-y-2z=-1

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Please help me with this system. I'm not getting the y or z. -x+2y+z=2 3x+y+z=12 x-y-2z=-1

Mathematics
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(3,2,1)
Can u explain it to me please?
are you supposed to use elimation?

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Other answers:

Either elimination or substitution
ok we can eleminate z first
satellite, i wasnt done, i still needed helpp :/
\[-x+2y+z=2\] \[ 3x+y+z=12\]
subtract and get \[-4x+y=-10\] as one equation with no z in it
now \[3x+y+z=12\] \[ x-y-2z=-1\] multiply first equation by 2 get \[6x+2y+2z=24\] \[x-y-2z=-1\] add and get \[7x+y=23\]
now we have \[-4x+y=-10\] and \[7x+y=23\] so solve
subtact second one from first and get \[-11x=-33\] making \[x=3\] now substitute back to find y, and then z
Where did the y go in the -4x+y=-10 and 7x+y=23
i subtracted the second equation from the first
oh you multiplied by -1
or if you prefer, multiply the second by -1 and then add,
yes exactly it is the same thing
ok I got it finally thank you so much for your help
\[-4x+y=-10\] \[-7x-y=-23\] \[-11x=-33\] etc yw

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