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yrivers36
Group Title
Please help me with this system. I'm not getting the y or z.
x+2y+z=2
3x+y+z=12
xy2z=1
 2 years ago
 2 years ago
yrivers36 Group Title
Please help me with this system. I'm not getting the y or z. x+2y+z=2 3x+y+z=12 xy2z=1
 2 years ago
 2 years ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.1
(3,2,1)
 2 years ago

yrivers36 Group TitleBest ResponseYou've already chosen the best response.0
Can u explain it to me please?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
are you supposed to use elimation?
 2 years ago

yrivers36 Group TitleBest ResponseYou've already chosen the best response.0
Either elimination or substitution
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
ok we can eleminate z first
 2 years ago

selenamalter Group TitleBest ResponseYou've already chosen the best response.0
satellite, i wasnt done, i still needed helpp :/
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[x+2y+z=2\] \[ 3x+y+z=12\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
subtract and get \[4x+y=10\] as one equation with no z in it
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
now \[3x+y+z=12\] \[ xy2z=1\] multiply first equation by 2 get \[6x+2y+2z=24\] \[xy2z=1\] add and get \[7x+y=23\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
now we have \[4x+y=10\] and \[7x+y=23\] so solve
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
subtact second one from first and get \[11x=33\] making \[x=3\] now substitute back to find y, and then z
 2 years ago

yrivers36 Group TitleBest ResponseYou've already chosen the best response.0
Where did the y go in the 4x+y=10 and 7x+y=23
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
i subtracted the second equation from the first
 2 years ago

yrivers36 Group TitleBest ResponseYou've already chosen the best response.0
oh you multiplied by 1
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
or if you prefer, multiply the second by 1 and then add,
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yes exactly it is the same thing
 2 years ago

yrivers36 Group TitleBest ResponseYou've already chosen the best response.0
ok I got it finally thank you so much for your help
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[4x+y=10\] \[7xy=23\] \[11x=33\] etc yw
 2 years ago
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