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then lets work thru it so I can catch up :)

ok thx

r^2+2r=0
r=0,-2 right?

at this point, it's just algebra which apparently, i'm very weak at

right

\[y=c_1e^{0x}+c_2e^{-2x}+y_p\]
\[y=c_1+c_2e^{-2x}+y_p\]

yp = At + B ; but we already have a constant so we need to up the ante
yp = At^2 + Bt ; and derive

yp = At^2 + Bt
yp'= 2At + B
yp''= 2A
agreed?

ah ok, i almost did that to solve for a but wasn't sure if it was correct, thank you

at^2 + bt = -t^2+ 5/2 t\[\]
\[y=c_1+c_2e^{-2x}-t^2+\frac 52 t \]