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anonymous
 4 years ago
Identify the domain and range for the graph of y = −2x2 − 8x + 1
anonymous
 4 years ago
Identify the domain and range for the graph of y = −2x2 − 8x + 1

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myininaya
 4 years ago
Best ResponseYou've already chosen the best response.5domain for all polynomials is all real numbers! :) now the best thing to do is put this into this form \[y=a(xh)^2+k \] to find the range This form is called vertex form by the way!

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.5or i guess you could look at visually but i don't care for that

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.5\[y=2(x^2+4x)+1\] \[y=2(x^2+4x+(\frac{4}{2})^2)+1+2(\frac{4}{2})^2\] Notice I added in a[b/2]^2 So I had to take it out! :) Now we have \[y=2(x+2)^2+1+2(\frac{16}{4})=2(x+2)^2+1+8\] \[y=2(x+2)^2+9\] I see that the vertex is (2,9) dw:1331078112680:dw That means the range is \[[\infty,9]\] Luis feedback group
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