anonymous
  • anonymous
write in matrix form: x'=y, y'=x+4 my teacher has not gone over this, I need help
Mathematics
chestercat
  • chestercat
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amistre64
  • amistre64
what is matrix form?
amistre64
  • amistre64
some sort of subject that this pertains to would help out as well
anonymous
  • anonymous
I am working with differential equations

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amistre64
  • amistre64
diffy qs, thats a start :)
amistre64
  • amistre64
and is this the start of a problem or like midways thru?
anonymous
  • anonymous
does x'=Ax+b help?
anonymous
  • anonymous
sorry, full question: write each system of differential equations in matrix form, i.e. x'=Ax+b
amistre64
  • amistre64
let me look that up to see if im familiar with it by another name ...
amistre64
  • amistre64
this looks useful http://tutorial.math.lamar.edu/Classes/DE/SystemsDE.aspx
anonymous
  • anonymous
yeah, its actually helping me on other questions, but not this one. But thanks. :)
amistre64
  • amistre64
is your vector [x',y'] by chance?
anonymous
  • anonymous
idk, a vector was not mentioned
amistre64
  • amistre64
x'=0x+y+0 y'=x+0y+4 \[\binom{x'}{y'}=\begin{pmatrix}0&1&0\\1&0&4 \end{pmatrix}\binom{x}{y}\] maybe
amistre64
  • amistre64
matrixes are vectors ...
amistre64
  • amistre64
\[\binom{x'}{y'}=\begin{pmatrix}0&1\\1&0 \end{pmatrix}\binom{x}{y}+\binom{0}{4}\] maybe
Mr.Math
  • Mr.Math
We have the system \(x'=0x+y \) \(y'=x+0y+4\). We can write this as: \({x' \choose y'}=\left[\begin{matrix}0 & 1 \\ 1 & 0\end{matrix}\right]{x\choose y}+{0\choose 4}.\)
amistre64
  • amistre64
yay!! thats good enough for validation to me :)
anonymous
  • anonymous
really? i thought it was more involved than that, cool. Thanks guys!
Mr.Math
  • Mr.Math
Although I think it can be solved without finding any eigenvalues or eigenvectors.

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