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anonymous
 4 years ago
write in matrix form: x'=y, y'=x+4
my teacher has not gone over this, I need help
anonymous
 4 years ago
write in matrix form: x'=y, y'=x+4 my teacher has not gone over this, I need help

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1some sort of subject that this pertains to would help out as well

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am working with differential equations

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1diffy qs, thats a start :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1and is this the start of a problem or like midways thru?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry, full question: write each system of differential equations in matrix form, i.e. x'=Ax+b

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1let me look that up to see if im familiar with it by another name ...

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1this looks useful http://tutorial.math.lamar.edu/Classes/DE/SystemsDE.aspx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah, its actually helping me on other questions, but not this one. But thanks. :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1is your vector [x',y'] by chance?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0idk, a vector was not mentioned

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1x'=0x+y+0 y'=x+0y+4 \[\binom{x'}{y'}=\begin{pmatrix}0&1&0\\1&0&4 \end{pmatrix}\binom{x}{y}\] maybe

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1matrixes are vectors ...

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[\binom{x'}{y'}=\begin{pmatrix}0&1\\1&0 \end{pmatrix}\binom{x}{y}+\binom{0}{4}\] maybe

Mr.Math
 4 years ago
Best ResponseYou've already chosen the best response.1We have the system \(x'=0x+y \) \(y'=x+0y+4\). We can write this as: \({x' \choose y'}=\left[\begin{matrix}0 & 1 \\ 1 & 0\end{matrix}\right]{x\choose y}+{0\choose 4}.\)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1yay!! thats good enough for validation to me :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0really? i thought it was more involved than that, cool. Thanks guys!

Mr.Math
 4 years ago
Best ResponseYou've already chosen the best response.1Although I think it can be solved without finding any eigenvalues or eigenvectors.
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