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and I'm so nerdy that I just have to know haha

hold on a sec please. i will brb

Sorry, im back.

wb

i know how to do this, just did this years ago. Let me recall.

Lol I have the same feeling about this thing!

I got as far as 64^(x-3)/42 = x
and then
(x-3)log(64/42) = log(x)

i think i found the way out, but i dont know how to write it,
How can we separate 64^(x – 3) ?

sec I'll look up exponential properties

Sure

http://www.efunda.com/math/exp_log/exp_relation.cfm

so I guess... 64^x/64^3 ?

i will refer to my register. let me chk

Asked for help.

Thank you for working at it though :-)

Lol, it's not wrong. that's for sure.

Well I've gotta go read linear algebra (which I don't want to do), so have a nice evening!

I'll check back in a little bit.

i will send u the solution.. i want to learn this as well

hahaha I've gotta stop getting people all curious!

ttyl

Lol, that's a no problem.

I think its 64^(x – 3) = 42^x

Oh damn that would make it so much easier

what is the level of the question i mean 2 say which class ??

Another user asked it and I was curious. It's precalc level I believe.

is -1/log(64) the answer?

u have taken out x common which wrong...... xln64-ln(42x) !=x(ln64-ln42)