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baddinlol

  • 2 years ago

An object is moving with constant speed in a straight line relative to the origin. The objects initial and final position vectors are respectively: u = i + 2j + 3k v = 2i + j -4k Find an expression for q, the position vector of the object when it has travelled a distance of x.

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  1. NotTim
    • 2 years ago
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    I'm doin the same stuff; I can't remember how to do this specifically; try your txtbook examples. sorry i didnt help much; studying for chem, bio and vectors test while doing eng assignment

  2. baddinlol
    • 2 years ago
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    Do you think this may be right, (v-u) + xu

  3. NotTim
    • 2 years ago
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    honestly couldnt tell you. it looks familiar, but im not sure

  4. baddinlol
    • 2 years ago
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    Ok Thanks anyway

  5. baddinlol
    • 2 years ago
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    help plz

  6. matricked
    • 2 years ago
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    i hope it is q=u +(x/sqrt(51) (v-u) (sqrt(51) for converting the drs of uv to dcs)

  7. baddinlol
    • 2 years ago
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    whats drs?

  8. matricked
    • 2 years ago
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    drs are direction ratios and dcs direction cosines

  9. baddinlol
    • 2 years ago
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    Thanks, I just understood it now.

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