Here's the question you clicked on:
baddinlol
An object is moving with constant speed in a straight line relative to the origin. The objects initial and final position vectors are respectively: u = i + 2j + 3k v = 2i + j -4k Find an expression for q, the position vector of the object when it has travelled a distance of x.
I'm doin the same stuff; I can't remember how to do this specifically; try your txtbook examples. sorry i didnt help much; studying for chem, bio and vectors test while doing eng assignment
Do you think this may be right, (v-u) + xu
honestly couldnt tell you. it looks familiar, but im not sure
i hope it is q=u +(x/sqrt(51) (v-u) (sqrt(51) for converting the drs of uv to dcs)
drs are direction ratios and dcs direction cosines
Thanks, I just understood it now.