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KarateChopKid Group Title

How would one differentiate the following: 2x+3/√(1-2x)

  • 2 years ago
  • 2 years ago

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  1. baddinlol Group Title
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    You can use the quotient rule.

    • 2 years ago
  2. baddinlol Group Title
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    Are you familiar with that?

    • 2 years ago
  3. KarateChopKid Group Title
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    yes I am familiar with this

    • 2 years ago
  4. baddinlol Group Title
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    so u = 2x+3 u' = 2 v = √(1-2x) v' = -1/√(1-2x)

    • 2 years ago
  5. baddinlol Group Title
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    The quotient rule says dy/dx = (u'v - uv')/v^2

    • 2 years ago
  6. KarateChopKid Group Title
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    ok and from there I begin to distribute, correct?

    • 2 years ago
  7. gurvinder Group Title
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    u can do it with quotient rule

    • 2 years ago
  8. baddinlol Group Title
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    Thats it follow (u'v - uv')/v^2

    • 2 years ago
  9. shana91 Group Title
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    |dw:1331119146075:dw| use this this is the division rule

    • 2 years ago
  10. shana91 Group Title
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    where u and v are two fuctions

    • 2 years ago
  11. KarateChopKid Group Title
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    I think that the square root in the function os throwing me off but I think that it would disappear in the deno. right? just leaving 1-2x on the bottom?

    • 2 years ago
  12. shana91 Group Title
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    exactly. you are right. square root dissapears. THat makes the sum a lot easier

    • 2 years ago
  13. .Sam. Group Title
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    • 2 years ago
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  14. KarateChopKid Group Title
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    Thank you! I was working it out and ended with the same result.

    • 2 years ago
  15. KarateChopKid Group Title
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    One final question... how would you find the eq. of a line tangent to the graph f(x) = √(2x+9) at x=0 ?

    • 2 years ago
  16. shana91 Group Title
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    take the first derivative of f(x) and equate all x to zero it gives the gradient of the tangent to the line at x=0

    • 2 years ago
  17. .Sam. Group Title
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    differentiate √(2x+9) then equate x=0 to the differentiated expression and get your gradient then create new equation using y-y1=m(x-x1)

    • 2 years ago
  18. shana91 Group Title
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    then use y=mx+c to get the equa. of the line

    • 2 years ago
  19. .Sam. Group Title
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    to find y1 just equate x=0 to original equation, y=√(2x+9), then get your y1

    • 2 years ago
  20. KarateChopKid Group Title
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    ok I am still a little shaky on deffrentiating a radical equation, would it be 1/2x+9 ?

    • 2 years ago
  21. .Sam. Group Title
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    |dw:1331120584519:dw|

    • 2 years ago
  22. shana91 Group Title
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    when u dof. the above one it'll be 1/(2x+9)^1/2

    • 2 years ago
  23. shana91 Group Title
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    you have forgot the 1/2

    • 2 years ago
  24. .Sam. Group Title
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    1/2 cancelled by 2

    • 2 years ago
  25. .Sam. Group Title
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    chain rule

    • 2 years ago
  26. KarateChopKid Group Title
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    ok so using the chain rule I use a fraction to symbolize the same radical function then move the 1/2 down and subtract by 1 to get my new power...got it

    • 2 years ago
  27. KarateChopKid Group Title
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    where did the "2" on the right come from though?

    • 2 years ago
  28. shana91 Group Title
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    not that 1/2 i meant the power 1/2|dw:1331120933568:dw| this should be what u getting aftr dif.

    • 2 years ago
  29. .Sam. Group Title
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    Example, |dw:1331120907510:dw|

    • 2 years ago
  30. KarateChopKid Group Title
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    Ok, so since it was in the deno. it was risen to the 2nd power and that is how is came to cancel the 1/2 right?

    • 2 years ago
  31. KarateChopKid Group Title
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    in the orig. differentation

    • 2 years ago
  32. .Sam. Group Title
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    the 2 in the numerator when differentiating, so it will cancel the 1/2

    • 2 years ago
  33. .Sam. Group Title
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    \[\huge \sqrt{x}=x ^{\frac{1}{2}}\]

    • 2 years ago
  34. KarateChopKid Group Title
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    ok I undrstand that example in omitting the radical but where did the 2 appear to make that cancel?

    • 2 years ago
  35. KarateChopKid Group Title
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    that is what is throwing me for a loop haha

    • 2 years ago
  36. .Sam. Group Title
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    the half of 2 is 1

    • 2 years ago
  37. shana91 Group Title
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    wait --look at this.. this how u solve n this is whr it got cancelled|dw:1331121592002:dw|

    • 2 years ago
  38. KarateChopKid Group Title
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    nevermind it came as a result of the y' and omitting the 9

    • 2 years ago
  39. KarateChopKid Group Title
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    or making 2x+9 just 2 right?

    • 2 years ago
  40. shana91 Group Title
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    I cant get u?

    • 2 years ago
  41. KarateChopKid Group Title
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    lol I can't get myself sometime haha but I think I understand that the 2 came as a result of taking the derivative of just 2x+9 resulting in just the 2 remaining...I think : /

    • 2 years ago
  42. shana91 Group Title
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    ohh that one..wait this is clear the prob.|dw:1331122282837:dw| cool?

    • 2 years ago
  43. KarateChopKid Group Title
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    yea... that I what I was trying to say but I guess my wording is off. I see where the 2 came from

    • 2 years ago
  44. shana91 Group Title
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    :)

    • 2 years ago
  45. KarateChopKid Group Title
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    Haha thanks. So then from there I plug in my x=0 to solve for that equation

    • 2 years ago
  46. KarateChopKid Group Title
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    and then use that solution in point-slope form

    • 2 years ago
  47. shana91 Group Title
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    that is correct. :) and then use thegradient equation to find the gradient...and the eq. of the line

    • 2 years ago
  48. salini Group Title
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    hey shana as u say the 2 in the denominator cannot get cancelled...

    • 2 years ago
  49. KarateChopKid Group Title
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    which gives me 3 from the graident and 1/3 for my derivative function

    • 2 years ago
  50. KarateChopKid Group Title
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    |dw:1331123039074:dw|

    • 2 years ago
  51. KarateChopKid Group Title
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    |dw:1331123158889:dw|

    • 2 years ago
  52. KarateChopKid Group Title
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    correct?

    • 2 years ago
  53. shana91 Group Title
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    correct

    • 2 years ago
  54. KarateChopKid Group Title
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    good deal! Thank you for all of you help and have an awesome day or night wherever you are!

    • 2 years ago
  55. KarateChopKid Group Title
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    |dw:1331123407516:dw|

    • 2 years ago
  56. shana91 Group Title
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    hhe it'll be night :) Anytime . I love guiding others not for money but for joy. :)

    • 2 years ago
  57. salini Group Title
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    again how di u agree abt that 2 getting cancelled in the differentaition part

    • 2 years ago
  58. shana91 Group Title
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    well salini, when u intergrate, the power comes to the front. ok? but when u again use the chain rule to integrate 2X u have to again multiply by 2. so they get cancelled off.

    • 2 years ago
  59. salini Group Title
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    oh yeah 2x part......

    • 2 years ago
  60. salini Group Title
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    we cant give u money here instead we give away medals!

    • 2 years ago
  61. shana91 Group Title
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    I really dont do this for money.... your medals will be highly appreciated.. I just joined today n already in level 10. :) This is a good place to give away my knowledge.

    • 2 years ago
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