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You can use the quotient rule.

Are you familiar with that?

yes I am familiar with this

so u = 2x+3
u' = 2
v = √(1-2x)
v' = -1/√(1-2x)

The quotient rule says dy/dx = (u'v - uv')/v^2

ok and from there I begin to distribute, correct?

u can do it with quotient rule

Thats it follow (u'v - uv')/v^2

|dw:1331119146075:dw| use this this is the division rule

where u and v are two fuctions

exactly. you are right. square root dissapears. THat makes the sum a lot easier

Thank you! I was working it out and ended with the same result.

then use y=mx+c to get the equa. of the line

to find y1 just equate x=0 to original equation, y=√(2x+9), then get your y1

ok I am still a little shaky on deffrentiating a radical equation, would it be 1/2x+9 ?

|dw:1331120584519:dw|

when u dof. the above one it'll be 1/(2x+9)^1/2

you have forgot the 1/2

1/2 cancelled by 2

chain rule

where did the "2" on the right come from though?

not that 1/2 i meant the power 1/2|dw:1331120933568:dw| this should be what u getting aftr dif.

Example,
|dw:1331120907510:dw|

in the orig. differentation

the 2 in the numerator when differentiating, so it will cancel the 1/2

\[\huge \sqrt{x}=x ^{\frac{1}{2}}\]

ok I undrstand that example in omitting the radical but where did the 2 appear to make that cancel?

that is what is throwing me for a loop haha

the half of 2 is 1

wait --look at this.. this how u solve n this is whr it got cancelled|dw:1331121592002:dw|

nevermind it came as a result of the y' and omitting the 9

or making 2x+9 just 2 right?

I cant get u?

ohh that one..wait this is clear the prob.|dw:1331122282837:dw| cool?

yea... that I what I was trying to say but I guess my wording is off. I see where the 2 came from

:)

Haha thanks. So then from there I plug in my x=0 to solve for that equation

and then use that solution in point-slope form

that is correct. :) and then use thegradient equation to find the gradient...and the eq. of the line

hey shana as u say the 2 in the denominator cannot get cancelled...

which gives me 3 from the graident and 1/3 for my derivative function

|dw:1331123039074:dw|

|dw:1331123158889:dw|

correct?

correct

good deal! Thank you for all of you help and have an awesome day or night wherever you are!

|dw:1331123407516:dw|

hhe it'll be night :) Anytime . I love guiding others not for money but for joy. :)

again how di u agree abt that 2 getting cancelled in the differentaition part

oh yeah 2x part......

we cant give u money here instead we give away medals!