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baddinlol
 3 years ago
An object is moving with constant speed in a straight line relative to O. the objects initial and final position vectors are respectively: u = i + 2j + 3k, v = 2i + j 4k, Find expression for q the position vector of the object when it has travelled a distance of x.
baddinlol
 3 years ago
An object is moving with constant speed in a straight line relative to O. the objects initial and final position vectors are respectively: u = i + 2j + 3k, v = 2i + j 4k, Find expression for q the position vector of the object when it has travelled a distance of x.

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baddinlol
 3 years ago
Best ResponseYou've already chosen the best response.0Ok, so I am having a bit of trouble with this one.

shana91
 3 years ago
Best ResponseYou've already chosen the best response.1is the diagram clear? dw:1331119632568:dw

shana91
 3 years ago
Best ResponseYou've already chosen the best response.1do you knwo how to take vector UV?

baddinlol
 3 years ago
Best ResponseYou've already chosen the best response.0I was thinking maybe q = (vu) + xu

shana91
 3 years ago
Best ResponseYou've already chosen the best response.1ok so it gives, UV as ij7k. when it is at distance 0, the vector is U, when it is in its end, the vector is V so when it has travelled X it should be in between right? so the answer when it is after x distance is, dw:1331119912201:dw

shana91
 3 years ago
Best ResponseYou've already chosen the best response.1when it is at x distance, it is the UNIT VECTOR*X i have found the unit vector by dividing by the scalar value of the vetor which is \[\sqrt{1^2+1^2+7^2}\]

baddinlol
 3 years ago
Best ResponseYou've already chosen the best response.0Why are we using the unit vector though?

shana91
 3 years ago
Best ResponseYou've already chosen the best response.1Unit vector means= what's the direction and the magnitude a particle will have when x=1(it has gone by one UNIT) so to get x units you have to multiply by X

baddinlol
 3 years ago
Best ResponseYou've already chosen the best response.0Oh.. ok That makes it clear.. Thanks for your help.
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