Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

calyne

  • 4 years ago

find the equation of the tangent line to the curve y = 4throot(x) at the point (1,1)

  • This Question is Closed
  1. Akshat4-10
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1331126566659:dw| At point (1,1) , slope ,m= 1/4 Now equation: y-y1= m (x-x1) y-1 = 1/4(x-1) Just simplify it now.

  2. ash2326
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @calyne did you understand?

  3. DHASHNI
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1331127430717:dw|

  4. DHASHNI
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    slope of the tangent =

  5. DHASHNI
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y'

  6. DHASHNI
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y=y'(x) +c 1=1/4(1) +c c=3/4 =>tangent line => y=1/4(x) +3/4

  7. calyne
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    uh how do you find the derivative

  8. calyne
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    or how is c 3/4

  9. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy