calyne
find the equation of the tangent line to the curve y = 4throot(x) at the point (1,1)



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Akshat410
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dw:1331126566659:dw
At point (1,1) , slope ,m= 1/4
Now equation: yy1= m (xx1)
y1 = 1/4(x1)
Just simplify it now.

ash2326
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@calyne did you understand?

DHASHNI
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dw:1331127430717:dw

DHASHNI
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slope of the tangent =

DHASHNI
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y'

DHASHNI
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y=y'(x) +c
1=1/4(1) +c
c=3/4
=>tangent line => y=1/4(x) +3/4

calyne
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uh how do you find the derivative

calyne
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or how is c 3/4