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calyne

  • 2 years ago

find the equation of the tangent line to the curve y = 4throot(x) at the point (1,1)

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  1. Akshat4-10
    • 2 years ago
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    |dw:1331126566659:dw| At point (1,1) , slope ,m= 1/4 Now equation: y-y1= m (x-x1) y-1 = 1/4(x-1) Just simplify it now.

  2. ash2326
    • 2 years ago
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    @calyne did you understand?

  3. DHASHNI
    • 2 years ago
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    |dw:1331127430717:dw|

  4. DHASHNI
    • 2 years ago
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    slope of the tangent =

  5. DHASHNI
    • 2 years ago
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    y'

  6. DHASHNI
    • 2 years ago
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    y=y'(x) +c 1=1/4(1) +c c=3/4 =>tangent line => y=1/4(x) +3/4

  7. calyne
    • 2 years ago
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    uh how do you find the derivative

  8. calyne
    • 2 years ago
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    or how is c 3/4

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