What is the volume of a triangular prism with a height of 7 meters and a base that is an equilateral triangle with sides of 2 meters?

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- anonymous

can someone please help

- anonymous

Sure, do you know that volume is area of the base times height?

- anonymous

Do you know how to get the area of a triangle?

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## More answers

- anonymous

If algebra is right, \(7 \sqrt{3} \; m^3 \)should be the answer.

- anonymous

Yes, I got 12.12, which is the same. Because you use hypothagorous theroem....

- anonymous

yea i do

- anonymous

thanks

- anonymous

@order: what is " hypothagorous theroem"?

- anonymous

I did not get it.... any one can explain?

- anonymous

haha, sorry. Pythagorous theorem... My teacher used to call it Hypothagorous theorem... Can't get it out now!

- anonymous

lol, you should sue that teacher :P

- anonymous

Yes! It's stuck. And I can't even spell pythagoras correctly :S

- anonymous

lol

- anonymous

perpendicular is sqrt 3... if you ll multiply it with 7 then it'll give area of plane?

- anonymous

Area of the base * Height * 1/3

- anonymous

sorry

- anonymous

so that = 21?

- anonymous

I got it.............. HATS OFF to @order
God bless you

- anonymous

http://www.aaastudy.com/geo79_x1.htm
Actually, we may all be wrong...?

- anonymous

It's just what FFM said.

- anonymous

the answer is this7√3m3

- anonymous

And what I thought before I got confused. @waqassaddique I think you got confused with a pyramid and a triangular prism.

- anonymous

Yes. Sorry. I was confused for a second between a pyramid and prism.. Won't happen again! :)

- anonymous

yes...... No problem @order, humans commit mistakes
so we did

- anonymous

now any one please tell me how answer is 7√3m3

- anonymous

It's that answer because the area of the base is the square root of 3 and 7 is the height.

- anonymous

@order : legend of mathematics...well done... thanks for your time for making my dull mind to understand

- anonymous

No problem! You might just have a tired head :p not a dull one.

- anonymous

may be

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