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help me please chris
when you have a negative exponent you just drop the value to the denominator
x^-3 is the same as 1/x^3
i guess thats what you are looking for since you give no further directions
what is it you are trying to do?
horizontal translation equation
did they give you a point?
no I just need to make up an equation and graphing
I am confused because normally for a horizontal translation a point is given
I have to create a horizontal function coming up with the points
so in other words i can plug 0 in for x and find my own point?
well x cant be 0 so lets do 1 then
so if x = 1 y = 2
2=2/(1-a)^3 2=2/1-a^3 2(1-a^3)=2 1-a^3=1 -a^3=0 a=0 which this would not change the equation, not having a point given confuses me >.<
if you used 2 for x your answer would be different
y=1/4 so 1/4= 2/(2-a)^3
wait wait ok, I'm confused now too without an point given. Ok so example : f(X)= 4^3-x is horizontal equation. How would that be solved?
so a agaon would = 0
meaning it would touch the line?
can't you plug in x value's ?
meaning the new equation which would be y=2(x-a)^3 would not be a change
if a is 0 there was no shift
this is why i dont like it when they do not give me a point to work with >.<
O.o me either