Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[2/\sqrt[3]{x}\]
oops 2/x^3
help me please chris

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

when you have a negative exponent you just drop the value to the denominator
x^-3 is the same as 1/x^3
so 2(1/x^3)=2/x^3
i guess thats what you are looking for since you give no further directions
what is it you are trying to do?
horizontal translation equation
sec
did they give you a point?
no I just need to make up an equation and graphing
I am confused because normally for a horizontal translation a point is given
I have to create a horizontal function coming up with the points
so in other words i can plug 0 in for x and find my own point?
yes
well x cant be 0 so lets do 1 then
ok
f(1)=2/(1)^3=2
so if x = 1 y = 2
2=2/(1-a)^3 2=2/1-a^3 2(1-a^3)=2 1-a^3=1 -a^3=0 a=0 which this would not change the equation, not having a point given confuses me >.<
if you used 2 for x your answer would be different
y=1/4 so 1/4= 2/(2-a)^3
14=2/(8-a^3)
1/4(8-a^3)=2
(1/4(8-a^3)=2)4
8-a^3=8
wait wait ok, I'm confused now too without an point given. Ok so example : f(X)= 4^3-x is horizontal equation. How would that be solved?
-a^3=0
so a agaon would = 0
meaning it would touch the line?
can't you plug in x value's ?
meaning the new equation which would be y=2(x-a)^3 would not be a change
y=2(x-0)^-3
if a is 0 there was no shift
ooh ok
this is why i dont like it when they do not give me a point to work with >.<
O.o me either

Not the answer you are looking for?

Search for more explanations.

Ask your own question