## hellowitsme 2 years ago 2x^-3

1. ChrisV

$2/\sqrt[3]{x}$

2. ChrisV

oops 2/x^3

4. ChrisV

when you have a negative exponent you just drop the value to the denominator

5. ChrisV

x^-3 is the same as 1/x^3

6. ChrisV

so 2(1/x^3)=2/x^3

7. ChrisV

i guess thats what you are looking for since you give no further directions

8. ChrisV

what is it you are trying to do?

horizontal translation equation

10. ChrisV

sec

11. ChrisV

did they give you a point?

no I just need to make up an equation and graphing

13. ChrisV

I am confused because normally for a horizontal translation a point is given

I have to create a horizontal function coming up with the points

15. ChrisV

so in other words i can plug 0 in for x and find my own point?

yes

17. ChrisV

well x cant be 0 so lets do 1 then

ok

19. ChrisV

f(1)=2/(1)^3=2

20. ChrisV

so if x = 1 y = 2

21. ChrisV

2=2/(1-a)^3 2=2/1-a^3 2(1-a^3)=2 1-a^3=1 -a^3=0 a=0 which this would not change the equation, not having a point given confuses me >.<

22. ChrisV

23. ChrisV

y=1/4 so 1/4= 2/(2-a)^3

24. ChrisV

14=2/(8-a^3)

25. ChrisV

1/4(8-a^3)=2

26. ChrisV

(1/4(8-a^3)=2)4

27. ChrisV

8-a^3=8

wait wait ok, I'm confused now too without an point given. Ok so example : f(X)= 4^3-x is horizontal equation. How would that be solved?

29. ChrisV

-a^3=0

30. ChrisV

so a agaon would = 0

meaning it would touch the line?

can't you plug in x value's ?

33. ChrisV

meaning the new equation which would be y=2(x-a)^3 would not be a change

34. ChrisV

y=2(x-0)^-3

35. ChrisV

if a is 0 there was no shift

ooh ok

37. ChrisV

this is why i dont like it when they do not give me a point to work with >.<