anonymous
  • anonymous
2x^-3
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[2/\sqrt[3]{x}\]
anonymous
  • anonymous
oops 2/x^3
anonymous
  • anonymous
help me please chris

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anonymous
  • anonymous
when you have a negative exponent you just drop the value to the denominator
anonymous
  • anonymous
x^-3 is the same as 1/x^3
anonymous
  • anonymous
so 2(1/x^3)=2/x^3
anonymous
  • anonymous
i guess thats what you are looking for since you give no further directions
anonymous
  • anonymous
what is it you are trying to do?
anonymous
  • anonymous
horizontal translation equation
anonymous
  • anonymous
sec
anonymous
  • anonymous
did they give you a point?
anonymous
  • anonymous
no I just need to make up an equation and graphing
anonymous
  • anonymous
I am confused because normally for a horizontal translation a point is given
anonymous
  • anonymous
I have to create a horizontal function coming up with the points
anonymous
  • anonymous
so in other words i can plug 0 in for x and find my own point?
anonymous
  • anonymous
yes
anonymous
  • anonymous
well x cant be 0 so lets do 1 then
anonymous
  • anonymous
ok
anonymous
  • anonymous
f(1)=2/(1)^3=2
anonymous
  • anonymous
so if x = 1 y = 2
anonymous
  • anonymous
2=2/(1-a)^3 2=2/1-a^3 2(1-a^3)=2 1-a^3=1 -a^3=0 a=0 which this would not change the equation, not having a point given confuses me >.<
anonymous
  • anonymous
if you used 2 for x your answer would be different
anonymous
  • anonymous
y=1/4 so 1/4= 2/(2-a)^3
anonymous
  • anonymous
14=2/(8-a^3)
anonymous
  • anonymous
1/4(8-a^3)=2
anonymous
  • anonymous
(1/4(8-a^3)=2)4
anonymous
  • anonymous
8-a^3=8
anonymous
  • anonymous
wait wait ok, I'm confused now too without an point given. Ok so example : f(X)= 4^3-x is horizontal equation. How would that be solved?
anonymous
  • anonymous
-a^3=0
anonymous
  • anonymous
so a agaon would = 0
anonymous
  • anonymous
meaning it would touch the line?
anonymous
  • anonymous
can't you plug in x value's ?
anonymous
  • anonymous
meaning the new equation which would be y=2(x-a)^3 would not be a change
anonymous
  • anonymous
y=2(x-0)^-3
anonymous
  • anonymous
if a is 0 there was no shift
anonymous
  • anonymous
ooh ok
anonymous
  • anonymous
this is why i dont like it when they do not give me a point to work with >.<
anonymous
  • anonymous
O.o me either

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