Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

\[2/\sqrt[3]{x}\]

oops 2/x^3

help me please chris

when you have a negative exponent you just drop the value to the denominator

x^-3 is the same as 1/x^3

so 2(1/x^3)=2/x^3

i guess thats what you are looking for since you give no further directions

what is it you are trying to do?

horizontal translation equation

sec

did they give you a point?

no I just need to make up an equation and graphing

I am confused because normally for a horizontal translation a point is given

I have to create a horizontal function coming up with the points

so in other words i can plug 0 in for x and find my own point?

yes

well x cant be 0 so lets do 1 then

ok

f(1)=2/(1)^3=2

so if x = 1 y = 2

if you used 2 for x your answer would be different

y=1/4 so
1/4= 2/(2-a)^3

14=2/(8-a^3)

1/4(8-a^3)=2

(1/4(8-a^3)=2)4

8-a^3=8

-a^3=0

so a agaon would = 0

meaning it would touch the line?

can't you plug in x value's ?

meaning the new equation which would be y=2(x-a)^3 would not be a change

y=2(x-0)^-3

if a is 0 there was no shift

ooh ok

this is why i dont like it when they do not give me a point to work with >.<

O.o me either