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hellowitsme

  • 3 years ago

2x^-3

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  1. ChrisV
    • 3 years ago
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    \[2/\sqrt[3]{x}\]

  2. ChrisV
    • 3 years ago
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    oops 2/x^3

  3. BlahAnswerMyQuestions!
    • 3 years ago
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    help me please chris

  4. ChrisV
    • 3 years ago
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    when you have a negative exponent you just drop the value to the denominator

  5. ChrisV
    • 3 years ago
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    x^-3 is the same as 1/x^3

  6. ChrisV
    • 3 years ago
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    so 2(1/x^3)=2/x^3

  7. ChrisV
    • 3 years ago
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    i guess thats what you are looking for since you give no further directions

  8. ChrisV
    • 3 years ago
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    what is it you are trying to do?

  9. BlahAnswerMyQuestions!
    • 3 years ago
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    horizontal translation equation

  10. ChrisV
    • 3 years ago
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    sec

  11. ChrisV
    • 3 years ago
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    did they give you a point?

  12. BlahAnswerMyQuestions!
    • 3 years ago
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    no I just need to make up an equation and graphing

  13. ChrisV
    • 3 years ago
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    I am confused because normally for a horizontal translation a point is given

  14. BlahAnswerMyQuestions!
    • 3 years ago
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    I have to create a horizontal function coming up with the points

  15. ChrisV
    • 3 years ago
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    so in other words i can plug 0 in for x and find my own point?

  16. BlahAnswerMyQuestions!
    • 3 years ago
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    yes

  17. ChrisV
    • 3 years ago
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    well x cant be 0 so lets do 1 then

  18. BlahAnswerMyQuestions!
    • 3 years ago
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    ok

  19. ChrisV
    • 3 years ago
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    f(1)=2/(1)^3=2

  20. ChrisV
    • 3 years ago
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    so if x = 1 y = 2

  21. ChrisV
    • 3 years ago
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    2=2/(1-a)^3 2=2/1-a^3 2(1-a^3)=2 1-a^3=1 -a^3=0 a=0 which this would not change the equation, not having a point given confuses me >.<

  22. ChrisV
    • 3 years ago
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    if you used 2 for x your answer would be different

  23. ChrisV
    • 3 years ago
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    y=1/4 so 1/4= 2/(2-a)^3

  24. ChrisV
    • 3 years ago
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    14=2/(8-a^3)

  25. ChrisV
    • 3 years ago
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    1/4(8-a^3)=2

  26. ChrisV
    • 3 years ago
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    (1/4(8-a^3)=2)4

  27. ChrisV
    • 3 years ago
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    8-a^3=8

  28. BlahAnswerMyQuestions!
    • 3 years ago
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    wait wait ok, I'm confused now too without an point given. Ok so example : f(X)= 4^3-x is horizontal equation. How would that be solved?

  29. ChrisV
    • 3 years ago
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    -a^3=0

  30. ChrisV
    • 3 years ago
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    so a agaon would = 0

  31. BlahAnswerMyQuestions!
    • 3 years ago
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    meaning it would touch the line?

  32. BlahAnswerMyQuestions!
    • 3 years ago
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    can't you plug in x value's ?

  33. ChrisV
    • 3 years ago
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    meaning the new equation which would be y=2(x-a)^3 would not be a change

  34. ChrisV
    • 3 years ago
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    y=2(x-0)^-3

  35. ChrisV
    • 3 years ago
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    if a is 0 there was no shift

  36. BlahAnswerMyQuestions!
    • 3 years ago
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    ooh ok

  37. ChrisV
    • 3 years ago
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    this is why i dont like it when they do not give me a point to work with >.<

  38. BlahAnswerMyQuestions!
    • 3 years ago
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    O.o me either

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