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pokemon23

  • 4 years ago

The product of two consecutive integers is three less than three times their sum.Find the integers.

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  1. matricked
    • 4 years ago
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    are the numbers 6 and 5

  2. dumbcow
    • 4 years ago
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    n(n+1) = 3(2n+1) -3

  3. Directrix
    • 4 years ago
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    Let x and x + 1 be the consecutive integers x(x+1) = 3(x + x + 1) – 3 x^2 + x = 3(2x + 1) – 3 x = 0 and x = 5 ?

  4. dumbcow
    • 4 years ago
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    n^2 -5n = 0

  5. pokemon23
    • 4 years ago
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    then we factor right

  6. dumbcow
    • 4 years ago
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    right pull out an n

  7. pokemon23
    • 4 years ago
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    n(n-5)=0

  8. pokemon23
    • 4 years ago
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    n=0

  9. pokemon23
    • 4 years ago
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    n=5

  10. pokemon23
    • 4 years ago
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    yup ;D

  11. Directrix
    • 4 years ago
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    So, the pairs are 0,1 and 5,6

  12. pokemon23
    • 4 years ago
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    how is it 0 and 1?

  13. pokemon23
    • 4 years ago
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    I understand how it 0 where did the 1 come from

  14. pokemon23
    • 4 years ago
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    Nvm now I know why its 0 and 1 because it consecutive integers going by one silly me

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