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What is exactly the moment of inertia all about? Clueless~

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it has a lot of formulas depending on the shape isnt it?
itis the rotational analogue of mass.yeah there are.u can find out by using parallel axis theorems and perpendicular axis theorem!!
i dont understand this question. Four particles A, B, C and D of mass 2 kg, 5 kg, 6 kg and 3 kg respectively are rigidly joined together by light rods to form a rectangle ABCD where AB=2a and BC=4a. Find the moment of inertia of this system of particles about an axis along AB..

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do i have to use I=Md\[^{2}\]
I had the exact same question in my mind when I started rotation. Unfortunately, none of my teachers could explain it that thouroughly. I had to do some self-research. :) You know what is inertia, right? A more massive mass requires more force to be moved. Mass is a measure of inertia. Now, when something rotates about its axis, the amount of force required to stop it does not depend only on the mass, but also a new thing - The distance from the axis. Try it. Try to move a stationary fan by giving it a strike it at its edge. It easily rotates. Then try to strike it somewhere near the center. It moves less. You have to apply more force to move something closer to the axis of rotation. So, now, the inertia of a rotating object is not only a function of mass, but also of the distance from the axis of rotation. You can try to find the kinetic energy of a rotating particle. Considering angular velocity for v, you will find the kinetic energy to be: \[mr ^{2} w ^{2}/2\]. The linear kinetic energy is \[mv ^{2}/2\] Compare these, and you will find that during rotation, the mass of a body is equivalent to mr^2. This new quantity is known as moment of inertia(you can clearly see moment of inertia increases with increasing distance from the axis) Did u get this?
Yeah! Great explanation.. I can finally picture it in my head.. :D bout my question i have to make the line of axis parallel to AB.. rite??
Yes, right. First find the moment of inertia about the centre of the system. Then use the parallel axis theorem(do u know it?)
about the centre??
so d=2a rite?? if from centre..
sorry.. im a bit slow..
Wait, you can do without the parallel axis theorem. The axis is AB. Take the coordinate axis along AB(x or y). Then find the distance of the four masses from the origin. Find the moment of inertia of each, and add them up. |dw:1331285211599:dw| I have considered A as the origin. Use the distance formula to calculate the distance of each mass from origin, and then use I=mr^2.
I would like to add something to the explanation. It is more difficult to stop the edges of a rotating fan, than the points closer to the center(because they have higher moment of inertia). The edges rotate at a higher speed than the others. You can observe that. The edges will appear completely blurred in a photograph, while the points close to the centre will be more visible
i have to find the inertia for A too?? even if it is the origin??
it will be zero
|dw:1331285964516:dw| this is from my lecturer's note.. what is with the delta x for?? and why is d the distance from the axis that we draw to the rod?? how should we know tat?? it explains that moment of inertia of typical element about XY = md2 (which i dont understand) n concluded Ixy=Md^2..
bout the delta x she wrote "Divide rod into elements each of length δx. "
A large part of classical mechanics(including newton's laws) deals with only particles. For a particle, we can easily say that its moment of inertia is mr^2. But not so, for large bodies. But the best we can do is divide(i.e. differentiate) large bodies into its constituent particles. We shall find the moment of inertia for a single particle, and add up for all of them(i.e. integrate) to find the net moment of inertia for the body. So, in the case of the rod, we have divided it into small elements of an extremely small length(we choose an extremely small length to make it equivalent to a particle) dx. The axis of rotation in a problem will always be given. You just have to find the distance of a particle from the axis. Since the element of length dx is a particle, we can say that it's moment of inertia is mr^2. Did u get it?
from the question tat i posted, the axis is the AB.. the particle is what? Is it the origin? Can i take B as the origin?
A, B, C and D are all particle masses. Yes, u cant take any point as the origin. But make sure you calculate the distances correctly
i cant?? But how do i noe which one to take as the origin?? the axis is AB so i shud take whether A or B as the origin.. am i rite??
sorry, typing mistake. You CAN take any point as the origin, but it would be more preferable to take A or B as origin because they lie on the axis
What if i take C and D?? What will happen??
Oh wait, I was correct when I had mistyped! See AB is the axis, which means A and B are gonna remain stationary. But C and D are going to move, continously changing their positions. So, it does not make sense to take either of them as origin. So take either A or B only as origin. This happens only in rotation. Otherwise, you CAN take any point as origin
Thanks! You really helped a LOT.. im not clueless anymore (in the mean time).. Bye..! ^^
Btw thanks for being patient with me..
No problem at all. Where are you from?
Mandy_Nakamoto: In simple manner moment of inertia is the mass which appose the rotational motion of any body. in the linear motion it is mass and in rotational motion it just named as moment of inertia.....the moment of inertia depends on the shape of the body.and we calculate the moment of inertia of any regular shape body by integratio method..such as moment of inertia circle is mr^2.where m is mass and r is the radius of that circle..we apply following integeration formula: dI=dmr^2... when mass is variable and dI is the moment of inertia of small part which has mass dm.... i hope that you will get your answer....

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