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xEnOnn
Group Title
Can someone show me the steps to this differentiation? \[\frac { d }{ dx } { 2 }^{ x }\]
How should I start with differentiating this?
 2 years ago
 2 years ago
xEnOnn Group Title
Can someone show me the steps to this differentiation? \[\frac { d }{ dx } { 2 }^{ x }\] How should I start with differentiating this?
 2 years ago
 2 years ago

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arcticf0x Group TitleBest ResponseYou've already chosen the best response.0
Take log on both sides, y=2^x
 2 years ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.3
http://www.youtube.com/watch?v=sSE6_fK3mu0
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
\[y=2^{x}\] \[lny=xln2\] \[[lny]\prime=\ln2\] \[y'/y=\ln2\] \[y'=\ln2*y'\] \[y'=2^{x}*\ln2\]
 2 years ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.3
d/dx e^x : by d/dx ln(x) Given : d/dx ln(x) = 1/x; Chain Rule; d/dx x = 1. (1) d/dx ln(e^x) = d/dx x = 1 d/dx ln(e^x) = d/du ln(u) d/dx e^x (Set u=e^x) = 1/u d/dx e^x = 1/e^x d/dx e^x = 1 (equation 1) d/dx e^x = e^x
 2 years ago

xEnOnn Group TitleBest ResponseYou've already chosen the best response.0
ohh...Thank you!!!
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
sorry, second to the last line should read y' = ln2 * y
 2 years ago
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