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Dumb_as_a_Duck

  • 2 years ago

Given,

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  1. satellite73
    • 2 years ago
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    taken

  2. atjari
    • 2 years ago
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    what is given?

  3. Dumb_as_a_Duck
    • 2 years ago
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    A = {\[{x:-2\le x-1\le4,x \in R} \]} and B = {\[x: -5 \le x-1 \le 2, x \in R\]} Represent A-B on a number line.

  4. Dumb_as_a_Duck
    • 2 years ago
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    Is this right|dw:1331386408686:dw|

  5. Dumb_as_a_Duck
    • 2 years ago
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    ?

  6. satellite73
    • 2 years ago
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    \[A=\{x:-2\le x-1\le4,x \in R\}\] solve for x get \[A=\{x:-1\le x-1\le5,x \in R\}\]

  7. satellite73
    • 2 years ago
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    that was wrong, solve for x get \[A=\{x:-1\le x\le5,x \in R\}\]

  8. Dumb_as_a_Duck
    • 2 years ago
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    you mean -1 less than or equal to x less than or equal to 5. theres no -1/

  9. TuringTest
    • 2 years ago
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    yeah, start with drawing both A and B then remove the B part of the line what is left is A-B

  10. satellite73
    • 2 years ago
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    similarly \[B=\{x:-4\le x\le3,x \in R\}\]

  11. satellite73
    • 2 years ago
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    and i assume A-B means what is in A that is not in B

  12. satellite73
    • 2 years ago
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    which would be (3,5]

  13. TuringTest
    • 2 years ago
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    |dw:1331388526284:dw|

  14. TuringTest
    • 2 years ago
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    |dw:1331388708918:dw|um... what do we do with the part on the left satellite?

  15. TuringTest
    • 2 years ago
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    @satellite73 do we ignore the left-over part from B to the left of -1 ?

  16. Dumb_as_a_Duck
    • 2 years ago
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    so the numbers that come under A-B are.....? (just clarifing)

  17. TuringTest
    • 2 years ago
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    to quote satellite: "and i assume A-B means what is in A that is not in B which would be (3,5]"

  18. Dumb_as_a_Duck
    • 2 years ago
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    shouldnt it be (4,5)? :/

  19. Mani_Jha
    • 2 years ago
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    It should be (3,5) because A is (-1,5) and B is (-4,3) |dw:1331393158512:dw| Just cancel out the common part. Did u get it from the figure?

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