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anilorap

Abstract Algebra Question: Let R be an equivalence relation on the set of real differentiable functions defined by fRg iff f and g has the same first derivative, i.e. f' = g'. Determine the equivalence classes of f for each f element of R.

  • 2 years ago
  • 2 years ago

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  1. KingGeorge
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    The equivalence class of f would just be the set of functions such that every function in the set is equal to f plus a constant term (The derivative of a constant term is 0).

    • 2 years ago
  2. anilorap
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    so should i define f. that means should i specify f in order to find the classes?

    • 2 years ago
  3. KingGeorge
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    f is just a real differentiable function. The most important thing is to define what a constant is. In this case, you should define the constant by saying it's a continuous differentiable function such that it's first derivative is 0.

    • 2 years ago
  4. anilorap
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    so can i say x^2/R= X^2+C, C= is a constant

    • 2 years ago
  5. anilorap
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    or ax^2+bx+C , a,b,c are constant.. can i define the classes like that?

    • 2 years ago
  6. KingGeorge
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    Partially. The only problem with defining classes like that, is you would have an infinite number of definitions, and you wouldn't include function like sin(x) and \(e^x\). Rather, I might recommend a definition similar to the following...

    • 2 years ago
  7. KingGeorge
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    Let \(f, g, h, a\) be continuous differentiable functions on the set of real numbers, and define an equivalence relation R such that \(f\text{R} g \;\Leftrightarrow \; f'=g'\). Then \(h\) is in the equivalence class of \(f\) iff \(h=f+a\) where \(a\;'=0\)

    • 2 years ago
  8. anilorap
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    mmm.. sounds good.. i think ill never come up with that.. :( why?

    • 2 years ago
  9. KingGeorge
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    It just takes practice. When I first started doing this, it took me a while to get used to it. Just make sure to proofread your definitions.

    • 2 years ago
  10. anilorap
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    thank you very much

    • 2 years ago
  11. KingGeorge
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    You're welcome.

    • 2 years ago
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