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anonymous
 4 years ago
how do u use trigonometry to determine an angle of an isosceles triangle??
anonymous
 4 years ago
how do u use trigonometry to determine an angle of an isosceles triangle??

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ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2Supposedly we are given the sides of isosceles triangle. If we draw a perpendicular from the vertex to the third side (two other sides are equal). It'll bisect the third side. dw:1331409664200:dw

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2We need to find the two angles x and the third angle y we know \[ \cos \theta= \frac{base}{hypotenuse}\] here \[\cos x= \frac{b/2}{a}\] from this we can find x and y=1802x

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0angles are determined by undoing a ratio

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0trig(angle) = ratio angle = arctrig(ratio)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0which angle are you interested in finding?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0there are 3 angles in a triangle :) I assume you mean the base angles?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0in order to determine the solution to any triangle we need a few bits of information to deduce the unknowns with

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0do you have a particular example we can work on?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0unfortunately...no :( its a studyguide for finals and i'm reviewing

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0well, there are 2 "laws" that can be used when we have certain information; one is the law of sines and the other is a more adaptable form of the pythag thrm

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0law of sines equates angles with the length of the side opposite the angle \[\frac{sin(C)}{c}=\frac{sin(B)}{b}=\frac{sin(C)}{c}\] dw:1331413584401:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0the law of cosines is the more general form of the pythag thrm: \[c^2=a^2+b^22ab\ cos(C)\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0when the angle C is 90 degrees; that simply reverts the the usual: c^2=a^2+b^2

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0the law of cosines is good for determing the length of sides; and the law of sines is easier to implement once you know the ratio of angles and sides
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