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JuanitaM
 2 years ago
Best ResponseYou've already chosen the best response.0i would do this in 3 steps multiply 1 by 2 then that answer by 3rd and that answer by 4th

Mr.Math
 2 years ago
Best ResponseYou've already chosen the best response.1\((x+1)(x+2)(x+3)(x+4)1=(x^4+10x^3+25x^2)+10x^2+50x+23\) \(=(x^2+5x)^2+10(x^2+5x)+23=0.\) Now put \(u=x^2+5x\) and solve the quadratic equation in \(u\), then solve for \(x\).

Mr.Math
 2 years ago
Best ResponseYou've already chosen the best response.1Let me know if there's anything you don't understand.
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