yociyoci

Solve (x+1)(x+2)(x+3)(x+4)=1 by hand

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JuanitaM

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i would do this in 3 steps
multiply 1 by 2
then that answer by 3rd
and that answer by 4th

JuanitaM

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|dw:1331416764128:dw|

yociyoci

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i don't understand...

Mr.Math

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\((x+1)(x+2)(x+3)(x+4)-1=(x^4+10x^3+25x^2)+10x^2+50x+23\)
\(=(x^2+5x)^2+10(x^2+5x)+23=0.\)
Now put \(u=x^2+5x\) and solve the quadratic equation in \(u\), then solve for \(x\).

Mr.Math

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Let me know if there's anything you don't understand.

yociyoci

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o i see

yociyoci

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Thank you!!

Mr.Math

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You're welcome!