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yociyoci

  • 4 years ago

Solve (x+1)(x+2)(x+3)(x+4)=1 by hand

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  1. JuanitaM
    • 4 years ago
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    i would do this in 3 steps multiply 1 by 2 then that answer by 3rd and that answer by 4th

  2. JuanitaM
    • 4 years ago
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    |dw:1331416764128:dw|

  3. yociyoci
    • 4 years ago
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    i don't understand...

  4. Mr.Math
    • 4 years ago
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    \((x+1)(x+2)(x+3)(x+4)-1=(x^4+10x^3+25x^2)+10x^2+50x+23\) \(=(x^2+5x)^2+10(x^2+5x)+23=0.\) Now put \(u=x^2+5x\) and solve the quadratic equation in \(u\), then solve for \(x\).

  5. Mr.Math
    • 4 years ago
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    Let me know if there's anything you don't understand.

  6. yociyoci
    • 4 years ago
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    o i see

  7. yociyoci
    • 4 years ago
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    Thank you!!

  8. Mr.Math
    • 4 years ago
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    You're welcome!

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