At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
thats not one of my options though. (3x + 1) (3x + 3) (3x – 1) None of the above
\[3x^2+9x+x+3\] I just found two factors of 3(3) that added up to be 10 Factor this by grouping
What factors does 3x^2 and 9x have in common?
the factors they have in common is 3
and x right?
\[3x(x+3)+1(x+3)\] Now we have two terms. What do these two terms have in common?
so the answer is none of the above because its not one of my options
we aren't done
I was just asking you what 3x^2 and 9x had in common so that we can factor this beast
both have 3x in common?
right so from the first two terms i factored out 3x giving me \[3x(x+3)+x+3\]
But we can write this as \[3x(x+3)+1(x+3)\] since 1(x+3) is still x+3
now what factors does 3x(x+3) and 1(x+3) have in common besides the factor 1?
no they both have the factor (x+3) in common
so the answer is (3x + 1)
x+3 and 3x+1 are both factors of the polynomial given
x+3 & 3x+1 are the factors