anonymous
  • anonymous
The safety mechanism for an elevator involves a suspension spring at the bottom of the elevator shaft and a safety clamp which applies a constant 17000N frictional force to the elevator. The spring should have a spring constant so that it is able to stop the elevator over a compression distance 2.00m If the 2000kg elevator is falling at 4m/s when it first comes into contact with the spring what should the force constant of the spring be? i am not sure if i should consider the Work with regards to gravity or just use energy from kinetic energy to solve.
Physics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
You may apply Work-Energy theorem :- Work done by all the forces = Change in K.E of the system.

Looking for something else?

Not the answer you are looking for? Search for more explanations.