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atjari Group Title

Plssssss help.

  • 2 years ago
  • 2 years ago

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  1. atjari Group Title
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    |dw:1331452540087:dw|

    • 2 years ago
  2. atjari Group Title
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    • 2 years ago
  3. atjari Group Title
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    pls see the attachment for the question

    • 2 years ago
  4. Mani_Jha Group Title
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    Efficiency is the ratio of the energy given to the system, to the net work done by the system. Now, can you tell me how will you find the net work done by the system from the graph?

    • 2 years ago
  5. SidharthSahoo Group Title
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    Hey Mani come to chat box

    • 2 years ago
  6. atjari Group Title
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    Net work=P2(V1-V2)-delta U

    • 2 years ago
  7. Mani_Jha Group Title
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    Well, actually the net work done by the system in a cyclic process is the area of the closed graph. Lets see how much work we have done to the system From 1 to 2, the work done is P2(V2-V1) From 2 to 3, no work is done From 3 to 1, the work done is (P3V2-P2V1)/(gamma -1) The work done by us is the sum of all the above. The work done by the gas is : W(1,2)+W(2,3)-W(3,1) Find the ratios of work done by gas, to work done by us. That should be the efficiency.

    • 2 years ago
  8. atjari Group Title
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    Can u explain hw u got (P3V2-P2V1)/(gamma -1) for 3to1

    • 2 years ago
  9. Mani_Jha Group Title
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    The work done by a gas in an adiabatic process is : \[(Pinitial \times Vinital-Pfinal \times Vfinal)/(\gamma-1)\] You can also prove this. Now, is it ok?

    • 2 years ago
  10. atjari Group Title
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    Ha k. Thanx a lot.

    • 2 years ago
  11. atjari Group Title
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    |dw:1331455348197:dw|

    • 2 years ago
  12. atjari Group Title
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    @Mani Jha

    • 2 years ago
  13. Mani_Jha Group Title
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    Hey, let me calculate and see. I will post as soon as I do this

    • 2 years ago
  14. atjari Group Title
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    Ha k. Thanx.

    • 2 years ago
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