anonymous
  • anonymous
Plssssss help.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1331452540087:dw|
anonymous
  • anonymous
pls see the attachment for the question

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Mani_Jha
  • Mani_Jha
Efficiency is the ratio of the energy given to the system, to the net work done by the system. Now, can you tell me how will you find the net work done by the system from the graph?
anonymous
  • anonymous
Hey Mani come to chat box
anonymous
  • anonymous
Net work=P2(V1-V2)-delta U
Mani_Jha
  • Mani_Jha
Well, actually the net work done by the system in a cyclic process is the area of the closed graph. Lets see how much work we have done to the system From 1 to 2, the work done is P2(V2-V1) From 2 to 3, no work is done From 3 to 1, the work done is (P3V2-P2V1)/(gamma -1) The work done by us is the sum of all the above. The work done by the gas is : W(1,2)+W(2,3)-W(3,1) Find the ratios of work done by gas, to work done by us. That should be the efficiency.
anonymous
  • anonymous
Can u explain hw u got (P3V2-P2V1)/(gamma -1) for 3to1
Mani_Jha
  • Mani_Jha
The work done by a gas in an adiabatic process is : \[(Pinitial \times Vinital-Pfinal \times Vfinal)/(\gamma-1)\] You can also prove this. Now, is it ok?
anonymous
  • anonymous
Ha k. Thanx a lot.
anonymous
  • anonymous
|dw:1331455348197:dw|
anonymous
  • anonymous
@Mani Jha
Mani_Jha
  • Mani_Jha
Hey, let me calculate and see. I will post as soon as I do this
anonymous
  • anonymous
Ha k. Thanx.

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