A community for students.
Here's the question you clicked on:
 0 viewing
Boxman61
 4 years ago
Solve:
___ ______
√x2 1 = √2(x3)
Boxman61
 4 years ago
Solve: ___ ______ √x2 1 = √2(x3)

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0square both sides to get (x2)2\[\sqrt{x2}\]+1=2x6 x12\[\sqrt{x2}/]=2x6 2\[\sqrt{x2}\]=x+5 \[\sqrt{x2}\]=x+5/2 square both sides again to get x2=(x+5/2)^2 x=(x+5/2)^2+2 x=(x^210x+25)/4 +2 4x=x^210x+27 x^214x+27=0 quadratic from there

Boxman61
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x2} 1 = \sqrt{2(x3)}\] \[(\sqrt{x2})^{2}  (1)^{2} = \sqrt{2x6}\] \[x21 = 2x6 \] \[x3 = 2x6\] \[x = 3\] x=3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no you have o square te entire leftside so its (sqrt(x2)1)^2 so you get 2sqrt(x2)+(x2)+1=2sqrt(x2)+x1

Boxman61
 4 years ago
Best ResponseYou've already chosen the best response.0hmm ok, my instructors answer is 3...trying to figure it out by your method

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0problem is that you cant square the terms individualy to clear the sqrt

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hmm.. it is x^214x33=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0doing itnot in my head at 2 am i got x^28x+12=0 but still not geting to "3"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0holy hell dropped the 2 on the right side gimme one sec

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@denebel has the correct quadratic and it also has one answer that is 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x+52*sqrt (x2) = 2x x+5 = 2x + 2*sqrt (x2) 5 = 2x + 2*sqrt (x2)  x 5x = 2*sqrt (x2) (5x)^2 = (2*sqrt (x2))^2 x^2  10x + 25 = 4x  8 0 = x^2 + 14x + 33 0 = x^2  14x  33

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x=3, x=11. Then you check each value by plugging it back into the original equation. Only x=3 checks out, therefore, x=3 is your answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oops Typo 0 = x^2 + 14x  33 0 = x^2  14x + 33

Boxman61
 4 years ago
Best ResponseYou've already chosen the best response.0your awesome, thank you... now to break it down so i learn it lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.