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MCronin
 3 years ago
Best ResponseYou've already chosen the best response.0square both sides to get (x2)2\[\sqrt{x2}\]+1=2x6 x12\[\sqrt{x2}/]=2x6 2\[\sqrt{x2}\]=x+5 \[\sqrt{x2}\]=x+5/2 square both sides again to get x2=(x+5/2)^2 x=(x+5/2)^2+2 x=(x^210x+25)/4 +2 4x=x^210x+27 x^214x+27=0 quadratic from there

Boxman61
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x2} 1 = \sqrt{2(x3)}\] \[(\sqrt{x2})^{2}  (1)^{2} = \sqrt{2x6}\] \[x21 = 2x6 \] \[x3 = 2x6\] \[x = 3\] x=3

MCronin
 3 years ago
Best ResponseYou've already chosen the best response.0no you have o square te entire leftside so its (sqrt(x2)1)^2 so you get 2sqrt(x2)+(x2)+1=2sqrt(x2)+x1

Boxman61
 3 years ago
Best ResponseYou've already chosen the best response.0hmm ok, my instructors answer is 3...trying to figure it out by your method

MCronin
 3 years ago
Best ResponseYou've already chosen the best response.0problem is that you cant square the terms individualy to clear the sqrt

Denebel
 3 years ago
Best ResponseYou've already chosen the best response.1Hmm.. it is x^214x33=0

MCronin
 3 years ago
Best ResponseYou've already chosen the best response.0doing itnot in my head at 2 am i got x^28x+12=0 but still not geting to "3"

MCronin
 3 years ago
Best ResponseYou've already chosen the best response.0holy hell dropped the 2 on the right side gimme one sec

MCronin
 3 years ago
Best ResponseYou've already chosen the best response.0@denebel has the correct quadratic and it also has one answer that is 3

Denebel
 3 years ago
Best ResponseYou've already chosen the best response.1x+52*sqrt (x2) = 2x x+5 = 2x + 2*sqrt (x2) 5 = 2x + 2*sqrt (x2)  x 5x = 2*sqrt (x2) (5x)^2 = (2*sqrt (x2))^2 x^2  10x + 25 = 4x  8 0 = x^2 + 14x + 33 0 = x^2  14x  33

Denebel
 3 years ago
Best ResponseYou've already chosen the best response.1x=3, x=11. Then you check each value by plugging it back into the original equation. Only x=3 checks out, therefore, x=3 is your answer.

Denebel
 3 years ago
Best ResponseYou've already chosen the best response.1Oops Typo 0 = x^2 + 14x  33 0 = x^2  14x + 33

Boxman61
 3 years ago
Best ResponseYou've already chosen the best response.0your awesome, thank you... now to break it down so i learn it lol
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