Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).
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Equation of a straight line: y = mx + c
Where m is the gradient
2 lines are parallel when the gradient of them both is equal
so as long as you have y = -3x then you can put any number after it
and the new line would be Parallell
y = -3x + 56434657567099123
y = -3x + 1
For it to pass through ( -1 , 6 ) then put the numbers in and see what you get ( but dont change the gradient )
y = -3x + 3 ( when x = -1 , y = 6 )
Well, parallel lines have the same slope (m) and a different y-intercept (b).
Slope intercept form is y=mx+b
Your original equation is y = -3x + 12.
-3 is the slope, and 12 is the y-intercept.
To find the y-intercept of the parallel line, we take the coordinates (-1, 6) and plug them into the equation y= -3x+b.
It looks like this 6= -3(-1)+b.
Solve for b.
So your parallel line equation is y= -3x+3.