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why.math
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Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).
 2 years ago
 2 years ago
why.math Group Title
Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).
 2 years ago
 2 years ago

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Steph_Rawr352 Group TitleBest ResponseYou've already chosen the best response.0
http://answers.yahoo.com/question/index?qid=20100722225418AAW0zGP
 2 years ago

Hershey_Kisses Group TitleBest ResponseYou've already chosen the best response.4
Equation of a straight line: y = mx + c Where m is the gradient 2 lines are parallel when the gradient of them both is equal so as long as you have y = 3x then you can put any number after it and the new line would be Parallell e.g. y = 3x + 56434657567099123 y = 3x + 1 For it to pass through ( 1 , 6 ) then put the numbers in and see what you get ( but dont change the gradient ) e.g. y = 3x + 3 ( when x = 1 , y = 6 )
 2 years ago

Hershey_Kisses Group TitleBest ResponseYou've already chosen the best response.4
Well, parallel lines have the same slope (m) and a different yintercept (b). Slope intercept form is y=mx+b Your original equation is y = 3x + 12. 3 is the slope, and 12 is the yintercept. To find the yintercept of the parallel line, we take the coordinates (1, 6) and plug them into the equation y= 3x+b. It looks like this 6= 3(1)+b. Solve for b. 6= 3(1)+b 6= 3+b 3= b So your parallel line equation is y= 3x+3.
 2 years ago

Hershey_Kisses Group TitleBest ResponseYou've already chosen the best response.4
wow @Steph_Rawr352 nice comeback lol
 2 years ago

Taufique Group TitleBest ResponseYou've already chosen the best response.0
let the equation of required line is m.since this is parallel to the given line hence both has same slope i.e m=3. hence the equation of required line will be (Y6)=3(X(1))=>Y=3X3+6=>Y=3X+3...
 2 years ago

why.math Group TitleBest ResponseYou've already chosen the best response.0
LOl thanks to everybody
 2 years ago
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