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anonymous
 4 years ago
Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).
anonymous
 4 years ago
Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://answers.yahoo.com/question/index?qid=20100722225418AAW0zGP

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Equation of a straight line: y = mx + c Where m is the gradient 2 lines are parallel when the gradient of them both is equal so as long as you have y = 3x then you can put any number after it and the new line would be Parallell e.g. y = 3x + 56434657567099123 y = 3x + 1 For it to pass through ( 1 , 6 ) then put the numbers in and see what you get ( but dont change the gradient ) e.g. y = 3x + 3 ( when x = 1 , y = 6 )

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, parallel lines have the same slope (m) and a different yintercept (b). Slope intercept form is y=mx+b Your original equation is y = 3x + 12. 3 is the slope, and 12 is the yintercept. To find the yintercept of the parallel line, we take the coordinates (1, 6) and plug them into the equation y= 3x+b. It looks like this 6= 3(1)+b. Solve for b. 6= 3(1)+b 6= 3+b 3= b So your parallel line equation is y= 3x+3.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow @Steph_Rawr352 nice comeback lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let the equation of required line is m.since this is parallel to the given line hence both has same slope i.e m=3. hence the equation of required line will be (Y6)=3(X(1))=>Y=3X3+6=>Y=3X+3...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0LOl thanks to everybody
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