Choose the correct product of (5x + 4)2.
25x2 + 40x + 16
25x2 − 16
25x2 + 16
25x2 − 40x + 16

- anonymous

Choose the correct product of (5x + 4)2.
25x2 + 40x + 16
25x2 − 16
25x2 + 16
25x2 − 40x + 16

- chestercat

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- anonymous

(5x+4)(5x+4)
Do you know how to use the FOIL method?

- anonymous

no

- anonymous

First, Outer, Inner, Last.
Your first terms that you need to multiply are 5x and 5x
5x*5x = 25x^2
Your outer terms that you need to multiply are 5x and 4.
5x*4 = 20x
Your inner terms that you need to multiply are 5x and 4.
5x*4 = 20x
You last terms that you need to multiply are 4 and 4.
4*4 = 16
So you have 25x^2, 20x, 20x, and 16 that you need to "combine."
25x^2 +20x +20x +16
= 25x^2 +40x +16

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## More answers

- anonymous

ah wow thanks so much!

- anonymous

Watch this :-)
http://www.youtube.com/watch?v=Twtdsp0a1Iw

- anonymous

- anonymous

is this correct

- anonymous

i still dont nderstand @phi

- phi

yes

- anonymous

i dont know anything?

- phi

see Khan's vide if you have time
http://www.khanacademy.org/math/algebra/multiplying-factoring-expression/multiplying-binomials/v/multiplying-binomials

- anonymous

i know that \(\color{lime}{\huge\ (5x+4)^2~}\) = 25x^2+16 but i dont understand if i add a 40x

- anonymous

@phi ?

- anonymous

in FOIL i use 5x^2+4^2 but dont get why did they add a 40x?

- phi

do you know what you get when you multiply
a(x+y)

- anonymous

ax+ay?

- phi

yes.
now what if a was "complicated"
in other words, if a was short-hand for (c+d) ?
we would get
(c+d)x + (c+d)y
(I just replaced "a" with its equivalent (c+d) )
now we do the "distributive property" again:
(c+d)x is the same as x(c+d), or, xc +xd
and
(c+d)y is cy + dy

- anonymous

ohh

- phi

in other words
(c+d)(x+y) can be written as
xc + xd +yc +yd
we get FOUR terms (which would come from using FOIL, if you learn that)

- anonymous

foil is first out inner last

- phi

with
(5x+4)(5x+4)
we will get 4 terms, but we can combine two of the terms, and get 3 terms in the end

- anonymous

BTW i hope you dont ge confused cuz it looks like (5x + 4)•2 but it is (5x + 4)^2

- phi

let's use the distributive idea to do
(5x+4)(5x+4)
First, let a= (5x+4) so it's easier to see what we are doing:
a(5x+4)= a*5x +a*4
now replace a with (5x+4)
(5x+4)*5x + (5x+4)*4
now expand both terms:
can you do that ?

- anonymous

yes

- anonymous

5x(5x+4)+4(5x+4)
25x^2•20x+20x+16
ohhhhhh
thx @phi

- phi

the first part
5x(5x+4) is written as 25x^2 +20x
so you get all together
\[ 25x^2 +20x +20x +16\]
the last step is notice we have 20 x's plus 20 more x's which is 40 x's. we write
\[ 25x^2 +40x +16\]

- some.random.cool.kid

hi

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