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calyne
Group Title
show me how to solve for x when 1/(x+1)^2 = [x/(x+1)  2]/(x1)
 2 years ago
 2 years ago
calyne Group Title
show me how to solve for x when 1/(x+1)^2 = [x/(x+1)  2]/(x1)
 2 years ago
 2 years ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.2
bunch of algebra, i will try to write it
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
\[\frac{x}{x+1}2=\frac{x2}{x+1}\] is a start
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
so right hand sides is \[\frac{x2}{(x+1)(x1)}\]
 2 years ago

calyne Group TitleBest ResponseYou've already chosen the best response.1
wait how did you start out like that
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
\[\frac{1}{(x+1)^2}=\frac{x2}{(x+1)(x1)}\] \[\frac{1}{x+1}=\frac{x2}{x1}\] \[x1=(x+1)(x2)\] \[x1=x^23x2\] \[x^2+3x+1=0\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
\[\frac{x}{x+1}2=\frac{x}{x+1}\frac{2(x+1)}{x+1}\] etc
 2 years ago

calyne Group TitleBest ResponseYou've already chosen the best response.1
still don't get thte first step talk about moronic what the flutter
 2 years ago
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