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anonymous
 4 years ago
Use the given specific heat capacity values below to calculate the percent error of the experimental specific heat capacity that you determined in Part I of the lab.
Known specific heat values — Iron: 0.444 J/g°C; Zinc: 0.390 J/g°C; Copper: 0.385 J/g°C, Aluminum: 0.900 J/g°C
 experimental  actual value  x 100 %
actual value
anonymous
 4 years ago
Use the given specific heat capacity values below to calculate the percent error of the experimental specific heat capacity that you determined in Part I of the lab. Known specific heat values — Iron: 0.444 J/g°C; Zinc: 0.390 J/g°C; Copper: 0.385 J/g°C, Aluminum: 0.900 J/g°C  experimental  actual value  x 100 % actual value

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Mani_Jha
 4 years ago
Best ResponseYou've already chosen the best response.1Well, what values for the specific heat capacities after your experiment? This question fits better into the Physics section.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.00.4 and 0.42 are my values

Mani_Jha
 4 years ago
Best ResponseYou've already chosen the best response.1These are for which substances?

Mani_Jha
 4 years ago
Best ResponseYou've already chosen the best response.1Well,consider only one value(that would be the average of the two values you got). Now get the actual value for the specific heat capacity of Ni.(you can get that from wikipediajust search 'nickel'). Now, find the difference of these two values, and divide it by the actual value. Multiply that by 100. That's your error percentage. Did you get it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i figured it out thanks1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, it more to physics i think..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In complete sentences, describe three sources of experimental error that could occur with this type of calorimetry lab. Explain, in detail, the effect that each specific error would have on the calculated specific heat capacity values. [ Close this window ]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Basically they are asking what could change the outcome of the experiment
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