Tia_Sweetheart17
  • Tia_Sweetheart17
this is a quadratic equation. i know the formula i just need to know how to do it. x^2+2x-24=0
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Do you know how to find your A, your B, any your C?
Tia_Sweetheart17
  • Tia_Sweetheart17
yeah
anonymous
  • anonymous
Wait- just re read the question. You're looking to use the quadratic formula, right?

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Tia_Sweetheart17
  • Tia_Sweetheart17
yes
anonymous
  • anonymous
Okay, good. So your a is 1, your b is 2, and your c is -24 so wherever you see an a in the formula, you put a 1, 2 for the b, and -24 for the c
anonymous
  • anonymous
So, the formula starts with (-b)^2. For that b, you'd put in 2. Do the same with the rest of the a's,b's, and c's and then just solve for x
anonymous
  • anonymous
Is that good or do you want to do the process together?
Tia_Sweetheart17
  • Tia_Sweetheart17
could we do it together to make sure i'm doing it right?
anonymous
  • anonymous
sure!
anonymous
  • anonymous
Alright, to heck with the stupid equation. I'm drawing it
anonymous
  • anonymous
|dw:1331687946988:dw|
anonymous
  • anonymous
Okay, so lets do the a's first
anonymous
  • anonymous
Since your a is 1, that's really simple because it only ever needs to get multiplied by the 2, and 2*1=1. So for a, you don't need to make any changes
anonymous
  • anonymous
Lets to b next. |dw:1331688080301:dw|
anonymous
  • anonymous
Sorry about that extra a; I forgot to mention it when we did a but it's the same situation. Because a is 1 and it's being multiplied, it makes no difference
anonymous
  • anonymous
Any questions so far?
Tia_Sweetheart17
  • Tia_Sweetheart17
no
anonymous
  • anonymous
Okay :) Now lets do c.|dw:1331688316770:dw|
anonymous
  • anonymous
And all of that is equal to x Now we need to solve for x
anonymous
  • anonymous
|dw:1331688455475:dw|
anonymous
  • anonymous
|dw:1331688519484:dw|
anonymous
  • anonymous
|dw:1331688549330:dw|
anonymous
  • anonymous
|dw:1331688578241:dw|
anonymous
  • anonymous
|dw:1331688607188:dw|
anonymous
  • anonymous
And that's all there is :)
Tia_Sweetheart17
  • Tia_Sweetheart17
thank you so much. i think i got it.
anonymous
  • anonymous
You're welcome :) medal?
Tia_Sweetheart17
  • Tia_Sweetheart17
sure
anonymous
  • anonymous
:)
Tia_Sweetheart17
  • Tia_Sweetheart17
could you help me again?

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