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  • S

How to find two positive x and y that minimize Q=x^2y if x+y+2 ?

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did u mean x+y=2?
  • S
oh, yes, sorry x+y=2
x+y = 2 y = 2-x Q=(x^2)*y = x^2(2-x) = 2x^2-x^3 Q' = 4x - 3x^2 = 0 x(4-3x)=0 x=0; 4-3x=0, -3x=-4; x=4/3

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@S did you leave? Because it looks like @Brutal was putting in some time to help you here...
  • S
no , i am steel here, just trying to understand this
  • S
Cool, no worries then - as you were ;)
okay just keep the positive positive value: x=4/3 x=4/3, but you know that y = 2- x, so y = 2-(4/3) = (6-4)/3 = 2/3
  • S
yes, was just thinking about y value =D, thank you soo much for your help!
Great job both of you @S and @Brutal. Thank you from OpenStudy!
np :)

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