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S

  • 2 years ago

How to find two positive x and y that minimize Q=x^2y if x+y+2 ?

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  1. Brutal
    • 2 years ago
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    did u mean x+y=2?

  2. S
    • 2 years ago
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    oh, yes, sorry x+y=2

  3. Brutal
    • 2 years ago
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    x+y = 2 y = 2-x Q=(x^2)*y = x^2(2-x) = 2x^2-x^3 Q' = 4x - 3x^2 = 0 x(4-3x)=0 x=0; 4-3x=0, -3x=-4; x=4/3

  4. cshalvey
    • 2 years ago
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    @S did you leave? Because it looks like @Brutal was putting in some time to help you here...

  5. S
    • 2 years ago
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    no , i am steel here, just trying to understand this

  6. S
    • 2 years ago
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    still*

  7. cshalvey
    • 2 years ago
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    Cool, no worries then - as you were ;)

  8. Brutal
    • 2 years ago
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    okay just keep the positive positive value: x=4/3 x=4/3, but you know that y = 2- x, so y = 2-(4/3) = (6-4)/3 = 2/3

  9. S
    • 2 years ago
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    yes, was just thinking about y value =D, thank you soo much for your help!

  10. cshalvey
    • 2 years ago
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    Great job both of you @S and @Brutal. Thank you from OpenStudy!

  11. Brutal
    • 2 years ago
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    np :)

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