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Mrbonez321
 3 years ago
Solve for x: 2x^2  4x  14 = 0
I have everything up to 2(x2)^2=6, but I do not know how to continue.
Mrbonez321
 3 years ago
Solve for x: 2x^2  4x  14 = 0 I have everything up to 2(x2)^2=6, but I do not know how to continue.

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Chlorophyll
 3 years ago
Best ResponseYou've already chosen the best response.22(x^2  2x  7) = 0 Δ = 4  ( 28) = 32 x = (4 ± 4 √2)/ 4 = 1 ± √2

Chlorophyll
 3 years ago
Best ResponseYou've already chosen the best response.2Oops, x = (4 ± 4 √2)/ 2 = 2 ± 2√2

Mrbonez321
 3 years ago
Best ResponseYou've already chosen the best response.0I dont understand Δ... I am only in Algebra II

S
 3 years ago
Best ResponseYou've already chosen the best response.12x^2  4x  14 = 0 divide everything by 2 in order to get x^2 by itself without the coefficient x^2  2x  7 = 0 and then use the quadratic formula (b+sqrt(b^2  4ac))/2a (2 +or sqrt(4  4*1*7))/2 (2 + sqrt(32)) / 2 and (2  sqrt(32))/2 2 + 4sqrt(2) / 2 and 2  4sqrt(2) / 2 1 + 2sqrt(2) and 1  2sqrt(2)

Chlorophyll
 3 years ago
Best ResponseYou've already chosen the best response.2That's quadratic formula in algebra II

Chlorophyll
 3 years ago
Best ResponseYou've already chosen the best response.2Only quadratic formula can solve any cases!

Chlorophyll
 3 years ago
Best ResponseYou've already chosen the best response.2S's result is perfect, not typo as mine!
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