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greysmither
Group Title
I'm trying to solve this but I honestly have no idea how to move forward. All I have done so far is this:
theta=tan^1(1)
Now I'm stuck <_>
 2 years ago
 2 years ago
greysmither Group Title
I'm trying to solve this but I honestly have no idea how to move forward. All I have done so far is this: theta=tan^1(1) Now I'm stuck <_>
 2 years ago
 2 years ago

This Question is Closed

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
@greysmither what's tan 45?
 2 years ago

Avva Group TitleBest ResponseYou've already chosen the best response.0
it is 135 degree ,, Aren't u allowed to use calculator??
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
Avva 135 is just one of the answer, it has several answers
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
tan1 only has one answer :)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
@amistre64 tan (theta)=1 will have several solutions
 2 years ago

Avva Group TitleBest ResponseYou've already chosen the best response.0
yup you can add 180 degrees and you'll figure out that 135 n 315 both have tan of 1
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
\[\tan \theta=1\] so \[\theta = n\pi +3\frac{\pi}{4}\] n=0, 1, 2, 3 and so on
 2 years ago

greysmither Group TitleBest ResponseYou've already chosen the best response.0
So this pretty much a unit circledependent problem?
 2 years ago

greysmither Group TitleBest ResponseYou've already chosen the best response.0
this is*
 2 years ago

greysmither Group TitleBest ResponseYou've already chosen the best response.0
Could it also be \[7\pi/4 + \pi n\]?
 2 years ago

greysmither Group TitleBest ResponseYou've already chosen the best response.0
since both of those quadrants create 1?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
Yeah it should be \[ n\pi \pm \pi/4\] n=1,2 ,3 and so on I missed that, it'd include \(7\pi/4 + n\pi\) also
 2 years ago

greysmither Group TitleBest ResponseYou've already chosen the best response.0
I thought that you couldn't include pi/4 and 5pi/4 in quadrants 1 and 3 because they equal 1 when I'm looking for 1?
 2 years ago

greysmither Group TitleBest ResponseYou've already chosen the best response.0
So confusing :(
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
Sorry, Just wait for some time, I'll help you:)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
Sorry kept you waiting:(
 2 years ago

greysmither Group TitleBest ResponseYou've already chosen the best response.0
Its okay I really appreciate your help
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
We have \[\tan x=1\] so x is eithere 3pi/4 , 7pi/4 and so on \[x= n\pi \pi/4\] if n=1 x=3 pi/4 n=2 x= 7 pi/4 so this will include all possible solutions. This is your answer
 2 years ago

greysmither Group TitleBest ResponseYou've already chosen the best response.0
So, just to clarify \[x=\pi/4+n \pi\] is the final answer. I can't thank you enough!! I wish I could give you 100 medals ;)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.3
Thanks Greysmither , this is the answer:)
 2 years ago
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