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anonymous
 4 years ago
The height of an equilateral rectangular prism decreases by two units. The new lateral area is less than the original by how much?
Answer
two times the area of the base
two times the perimeter of the base
two less than the the area of the base
two less than the perimeter of the base
I think it is C but im not sure
anonymous
 4 years ago
The height of an equilateral rectangular prism decreases by two units. The new lateral area is less than the original by how much? Answer two times the area of the base two times the perimeter of the base two less than the the area of the base two less than the perimeter of the base I think it is C but im not sure

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What's the formula for the area of the prism?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1331785747771:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's a rectangular prism. The lateral surface area is the area of the 4 sides, not including the base and the top.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the formula for the lateral surface area is Perimeter of base X height

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now, if the new height is decreased by two, so it is h2 so the area is : P x (h2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are you understanding so far?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[P \times ( h2) = P \times h  P \times 2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But, P x h is the area of the original prism! the above equation basically says: New Area = Old Area  P x 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No, P x 2 means Perimeter times 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you once again : )

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Glad to help, good luck!
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