## anonymous 4 years ago How do you solve 2sin^2 (theta) + cos(theta)=2?

1. anonymous

try substituting (sin^x)^2=1-(cos^x)^2

2. anonymous

60 OR 90 DEGREE

3. anonymous

$2\sin^2\theta+\cos \theta=2$ We know that: $\sin^2\theta = (1-\cos^2\theta)$ So we can substitute and get: $2(1-\cos^2\theta)+\cos \theta = 2$