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greysmither

  • 4 years ago

How do you solve 2sin^2 (theta) + cos(theta)=2?

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  1. ghass1978
    • 4 years ago
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    try substituting (sin^x)^2=1-(cos^x)^2

  2. MAYUR2345
    • 4 years ago
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    60 OR 90 DEGREE

  3. MrYantho
    • 4 years ago
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    \[2\sin^2\theta+\cos \theta=2\] We know that: \[\sin^2\theta = (1-\cos^2\theta)\] So we can substitute and get: \[2(1-\cos^2\theta)+\cos \theta = 2\]

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