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@myininaya @amistre64 How would you prove it?

f"(x) must be constant, right?

Why?

It doesn't have to be constant.

mr.math do you mean g is positive on those intervals...and g is negative on that interval...

I meant \(g'\) is positive on those interval and negative on that interval.

I know, I just wanted it to be constant I mean not any obvious reason, just like that.

I didn't defined it as a constant.

define*

Am I making sense Ishaan?

Of course, you're... it's me, who didn't

This problem is not difficult, but I'm missing something. What am I missing?!

Do you think I should ping Zarkon?

I think I have it. One minute.

You can ping him though, but he should not answer until I finish :P

Correct! I just noticed that :)

So we have to show that \(f'(2\pi)+g(0)\ge g(2\pi)+f'(0).\)

Zarkon's offline :(... @satellite73 @eseidl

i am thinking parts

oh i should pay attention. looks like mr.math did parts right?

Yes.

yeah

It is a given in the problem

ooooooooh ok i see i misinterpreted the last step

yes, sorry i see what you wrote, i simply read it wrong.