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Sirlw

  • 2 years ago

please help me !! Two friends live 28 miles apart on a straight road. One can bicycle 3 miles per hour faster than the other. They start at the same time and meet after cycling for 2 hours. What rate did each cycle?

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  1. Sirlw
    • 2 years ago
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    wait what did you do?

  2. JuanitaM
    • 2 years ago
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    |dw:1331857363801:dw|

  3. JuanitaM
    • 2 years ago
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    we did not get the same answer i read that problem retrice"three times faster" so you must multiply

  4. Sirlw
    • 2 years ago
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    yes and?

  5. JuanitaM
    • 2 years ago
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    Luis added 3 hours instead of multiplying

  6. Sirlw
    • 2 years ago
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    explain the equation please

  7. JuanitaM
    • 2 years ago
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    this is a distance problem. so D = RT 1. total distance is 28 2. first cycle rate of x and 2 time = 2x 3. second cycler rate of 3x and 2 time = 6x set both to equal full 28 solve for x x = 3.5 and to get the other rate it is 3x = 10.5

  8. Sirlw
    • 2 years ago
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    wait

  9. JuanitaM
    • 2 years ago
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    ok

  10. Sirlw
    • 2 years ago
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    nvm i got it

  11. JuanitaM
    • 2 years ago
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    ok.

  12. Sirlw
    • 2 years ago
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    i tink lol

  13. Sirlw
    • 2 years ago
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    *think

  14. JuanitaM
    • 2 years ago
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    Ques Luis - why are you not doing 3x instead of 3+x?

  15. Sirlw
    • 2 years ago
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    so you do the man 3x faster: 3x * 2 hours equal 6x Then you add the speed of the normal guy= 6x + 2x the distance is 28 so 8x=28 Simplify 3.5

  16. Chlorophyll
    • 2 years ago
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    Yep, 100% agree with Luis: 3mi/ hr faster = v + 3 I bet Juanita read 3 MILES instead of 3 MILES :P

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