anonymous
  • anonymous
please help me !! Two friends live 28 miles apart on a straight road. One can bicycle 3 miles per hour faster than the other. They start at the same time and meet after cycling for 2 hours. What rate did each cycle?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
wait what did you do?
anonymous
  • anonymous
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anonymous
  • anonymous
we did not get the same answer i read that problem retrice"three times faster" so you must multiply

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anonymous
  • anonymous
yes and?
anonymous
  • anonymous
Luis added 3 hours instead of multiplying
anonymous
  • anonymous
explain the equation please
anonymous
  • anonymous
this is a distance problem. so D = RT 1. total distance is 28 2. first cycle rate of x and 2 time = 2x 3. second cycler rate of 3x and 2 time = 6x set both to equal full 28 solve for x x = 3.5 and to get the other rate it is 3x = 10.5
anonymous
  • anonymous
wait
anonymous
  • anonymous
ok
anonymous
  • anonymous
nvm i got it
anonymous
  • anonymous
ok.
anonymous
  • anonymous
i tink lol
anonymous
  • anonymous
*think
anonymous
  • anonymous
Ques Luis - why are you not doing 3x instead of 3+x?
anonymous
  • anonymous
so you do the man 3x faster: 3x * 2 hours equal 6x Then you add the speed of the normal guy= 6x + 2x the distance is 28 so 8x=28 Simplify 3.5
anonymous
  • anonymous
Yep, 100% agree with Luis: 3mi/ hr faster = v + 3 I bet Juanita read 3 MILES instead of 3 MILES :P

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