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Sirlw
 3 years ago
please help me !!
Two friends live 28 miles apart on a straight road. One can bicycle 3 miles per hour faster than the other. They start at the same time and meet after cycling for 2 hours. What rate did each cycle?
Sirlw
 3 years ago
please help me !! Two friends live 28 miles apart on a straight road. One can bicycle 3 miles per hour faster than the other. They start at the same time and meet after cycling for 2 hours. What rate did each cycle?

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JuanitaM
 3 years ago
Best ResponseYou've already chosen the best response.0we did not get the same answer i read that problem retrice"three times faster" so you must multiply

JuanitaM
 3 years ago
Best ResponseYou've already chosen the best response.0Luis added 3 hours instead of multiplying

Sirlw
 3 years ago
Best ResponseYou've already chosen the best response.0explain the equation please

JuanitaM
 3 years ago
Best ResponseYou've already chosen the best response.0this is a distance problem. so D = RT 1. total distance is 28 2. first cycle rate of x and 2 time = 2x 3. second cycler rate of 3x and 2 time = 6x set both to equal full 28 solve for x x = 3.5 and to get the other rate it is 3x = 10.5

JuanitaM
 3 years ago
Best ResponseYou've already chosen the best response.0Ques Luis  why are you not doing 3x instead of 3+x?

Sirlw
 3 years ago
Best ResponseYou've already chosen the best response.0so you do the man 3x faster: 3x * 2 hours equal 6x Then you add the speed of the normal guy= 6x + 2x the distance is 28 so 8x=28 Simplify 3.5

Chlorophyll
 3 years ago
Best ResponseYou've already chosen the best response.1Yep, 100% agree with Luis: 3mi/ hr faster = v + 3 I bet Juanita read 3 MILES instead of 3 MILES :P
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