## GOODMAN 3 years ago Find the first 6 terms of each sequence: I will write down in equation editor.

1. imranmeah91

first time I've seen you here

2. GOODMAN

\[a _{1}=1, a _{2}=2, a _{n+2}=4a _{n+1}-3a _{n}\]

3. GOODMAN

Sorry, i take forever on this equation thingie.

4. imranmeah91

ok, let's find \[a_3\] together

5. GOODMAN

Okie dokie!

6. karatechopper

its like lil emu is in dsiguise helpin ya!;D lol i will leave ya alone now to get bak to hw

7. GOODMAN

Okay. Got it.

8. imranmeah91

\[a_3=a_{1+2}\] which mean n=1 using equation \[a_{2+1}=4a_{1+1}-3a_{1}\]

9. GOODMAN

wait..so n does not equal 2?

10. imranmeah91

no, I meant n=1

11. GOODMAN

Okie.

12. imranmeah91

\[a_{2+1}=4a_{1+1}−3a_1\] \[=a_{3}=4a_{2}−3a_1\] you know what a1 and a2 are

13. GOODMAN

Oh coolio!!! We can plug those numbers in.

14. imranmeah91

a_3=4(2)-3(1)=5

15. imranmeah91

let see you find a_4

16. GOODMAN

Okay, i got 5 for a_3

17. GOODMAN

Would i have to make n equal to 2?

18. imranmeah91

yes

19. GOODMAN

I got 14 for a_4

20. GOODMAN

Is that correct?

21. imranmeah91

yes

22. GOODMAN

YAAAYYY!!! now its soo simple for me!!

23. GOODMAN

I got this, thank you thank you!!!!

24. karatechopper

done yet ??????????????