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Find the first 6 terms of each sequence: I will write down in equation editor.
 2 years ago
 2 years ago
Find the first 6 terms of each sequence: I will write down in equation editor.
 2 years ago
 2 years ago

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imranmeah91Best ResponseYou've already chosen the best response.2
first time I've seen you here
 2 years ago

GOODMANBest ResponseYou've already chosen the best response.0
\[a _{1}=1, a _{2}=2, a _{n+2}=4a _{n+1}3a _{n}\]
 2 years ago

GOODMANBest ResponseYou've already chosen the best response.0
Sorry, i take forever on this equation thingie.
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.2
ok, let's find \[a_3\] together
 2 years ago

karatechopperBest ResponseYou've already chosen the best response.0
its like lil emu is in dsiguise helpin ya!;D lol i will leave ya alone now to get bak to hw
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.2
\[a_3=a_{1+2}\] which mean n=1 using equation \[a_{2+1}=4a_{1+1}3a_{1}\]
 2 years ago

GOODMANBest ResponseYou've already chosen the best response.0
wait..so n does not equal 2?
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.2
\[a_{2+1}=4a_{1+1}−3a_1\] \[=a_{3}=4a_{2}−3a_1\] you know what a1 and a2 are
 2 years ago

GOODMANBest ResponseYou've already chosen the best response.0
Oh coolio!!! We can plug those numbers in.
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.2
let see you find a_4
 2 years ago

GOODMANBest ResponseYou've already chosen the best response.0
Would i have to make n equal to 2?
 2 years ago

GOODMANBest ResponseYou've already chosen the best response.0
YAAAYYY!!! now its soo simple for me!!
 2 years ago

GOODMANBest ResponseYou've already chosen the best response.0
I got this, thank you thank you!!!!
 2 years ago

karatechopperBest ResponseYou've already chosen the best response.0
done yet ??????????????
 2 years ago
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