GOODMAN
Find the first 6 terms of each sequence: I will write down in equation editor.



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imranmeah91
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first time I've seen you here

GOODMAN
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\[a _{1}=1, a _{2}=2, a _{n+2}=4a _{n+1}3a _{n}\]

GOODMAN
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Sorry, i take forever on this equation thingie.

imranmeah91
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ok, let's find \[a_3\] together

GOODMAN
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Okie dokie!

karatechopper
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its like lil emu is in dsiguise helpin ya!;D lol i will leave ya alone now to get bak to hw

GOODMAN
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Okay. Got it.

imranmeah91
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\[a_3=a_{1+2}\]
which mean n=1
using equation
\[a_{2+1}=4a_{1+1}3a_{1}\]

GOODMAN
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wait..so n does not equal 2?

imranmeah91
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no, I meant n=1

GOODMAN
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Okie.

imranmeah91
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\[a_{2+1}=4a_{1+1}−3a_1\]
\[=a_{3}=4a_{2}−3a_1\]
you know what a1 and a2 are

GOODMAN
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Oh coolio!!! We can plug those numbers in.

imranmeah91
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a_3=4(2)3(1)=5

imranmeah91
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let see you find a_4

GOODMAN
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Okay, i got 5 for a_3

GOODMAN
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Would i have to make n equal to 2?

imranmeah91
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yes

GOODMAN
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I got 14 for a_4

GOODMAN
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Is that correct?

imranmeah91
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yes

GOODMAN
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YAAAYYY!!! now its soo simple for me!!

GOODMAN
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I got this, thank you thank you!!!!

karatechopper
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done yet
??????????????