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mslorraine

  • 4 years ago

√(9x+67=x+5=)

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  1. cyclects
    • 4 years ago
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    do u mean \[\sqrt{9x+67} = x+5 \] find x?

  2. mslorraine
    • 4 years ago
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    yes

  3. Avva
    • 4 years ago
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    now you need to square both sides so it will be \[9x+67 = (x+5)^{2}\] \[9x +67 = x ^{2} + 10x + 25\] \[x ^{2} + x -42 = 0\] I guess it is clear now :) note that you need to get rid of square roots in most problems by squaring you can get rid of it

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