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Math12: Geometric Sequences
The first three terms of a geometric sequence are
sqrt[4]{3},sqrt[8]{3}, and 1.
What is the fourth term?
 2 years ago
 2 years ago
Math12: Geometric Sequences The first three terms of a geometric sequence are sqrt[4]{3},sqrt[8]{3}, and 1. What is the fourth term?
 2 years ago
 2 years ago

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Hannah_AhnBest ResponseYou've already chosen the best response.0
I would really appreciate if you guys can show me steps by steps
 2 years ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Can you please right it clearly. Is it: \[\sqrt{4*3}?\]
 2 years ago

Hannah_AhnBest ResponseYou've already chosen the best response.0
.\[\sqrt[4]{3} , \sqrt[8]{3}, and 1.\]
 2 years ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Well, find the common ratio first.. \[\large \frac{T_{2}}{T_{1}} = \frac{\sqrt[8]{3}}{\sqrt[4]{3}} \] \[\large \frac{T_{3}}{T_{2}} = \frac{1}{\sqrt[8]{3}} \]
 2 years ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Then find the general term; the formula is: \[\large T_n = ar^{n1}\] To find the fourth term; sub in n = 4; where a is the first term of the sequence and r is the common ratio.
 2 years ago

Hannah_AhnBest ResponseYou've already chosen the best response.0
cool! thanks you!! that was helpful :)
 2 years ago
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