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Hannah_Ahn

  • 4 years ago

Math12: Geometric Sequences The first three terms of a geometric sequence are sqrt[4]{3},sqrt[8]{3}, and 1. What is the fourth term?

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  1. Hannah_Ahn
    • 4 years ago
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    I would really appreciate if you guys can show me steps by steps

  2. Mimi_x3
    • 4 years ago
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    Can you please right it clearly. Is it: \[\sqrt{4*3}?\]

  3. Mimi_x3
    • 4 years ago
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    write* lol

  4. Hannah_Ahn
    • 4 years ago
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    .\[\sqrt[4]{3} , \sqrt[8]{3}, and 1.\]

  5. Hannah_Ahn
    • 4 years ago
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    sorry about that :p

  6. Mimi_x3
    • 4 years ago
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    Well, find the common ratio first.. \[\large \frac{T_{2}}{T_{1}} = \frac{\sqrt[8]{3}}{\sqrt[4]{3}} \] \[\large \frac{T_{3}}{T_{2}} = \frac{1}{\sqrt[8]{3}} \]

  7. Mimi_x3
    • 4 years ago
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    Then find the general term; the formula is: \[\large T_n = ar^{n-1}\] To find the fourth term; sub in n = 4; where a is the first term of the sequence and r is the common ratio.

  8. Hannah_Ahn
    • 4 years ago
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    cool! thanks you!! that was helpful :)

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