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A 0.395kg blue bead slides on a frictionless, curved wire, starting from rest at point in the figure below, where h = 1.50 m. At point , the blue bead collides elastically with a 0.625kg green bead at rest. Find the maximum height the green bead rises as it moves up the wire.
 2 years ago
 2 years ago
A 0.395kg blue bead slides on a frictionless, curved wire, starting from rest at point in the figure below, where h = 1.50 m. At point , the blue bead collides elastically with a 0.625kg green bead at rest. Find the maximum height the green bead rises as it moves up the wire.
 2 years ago
 2 years ago

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TaufiqueBest ResponseYou've already chosen the best response.0
@mswitten Here.no fig is present.post fig .
 2 years ago

hoseinBest ResponseYou've already chosen the best response.0
blue bead's final velocity is 0after collide? if there is afig we use from that
 2 years ago

SinbearcianteBest ResponseYou've already chosen the best response.0
Theres no need for a figure if what you have written is all that the problem includes. Since this is on a frictionless surface and they collide elastically, it is a problem concerning the conservation of energy. So, U(initial)=U(final); m(1)gh(initial)=m(2)gh(final). Plug in your numbers and youll get it. (.948m)
 2 years ago

hoseinBest ResponseYou've already chosen the best response.0
you find green bead velocity from conversation of momentum between two time befor collide & after collide so use conservation of energy
 2 years ago

SinbearcianteBest ResponseYou've already chosen the best response.0
I use U(potential energy) for both b/c when it starts at rest it obviously has no kinetic energy and it is all potential. When the green bead is at its max height, its at rest (relatively) so its energy is also all in the form of potential energy (U).
 2 years ago

hoseinBest ResponseYou've already chosen the best response.0
you'r right but we ought be use two conservation of energy one's for finding velocity of green &2nd for finding h of green not using one relation
 2 years ago

SinbearcianteBest ResponseYou've already chosen the best response.0
Cant understand what hosein is trying to saying, but my answer is right.
 2 years ago
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