A 0.395-kg blue bead slides on a frictionless, curved wire, starting from rest at point in the figure below, where h = 1.50 m. At point , the blue bead collides elastically with a 0.625-kg green bead at rest. Find the maximum height the green bead rises as it moves up the wire.
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@mswitten Here.no fig is present.post fig .
blue bead's final velocity is 0after collide? if there is afig we use from that
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Theres no need for a figure if what you have written is all that the problem includes.
Since this is on a frictionless surface and they collide elastically, it is a problem concerning the conservation of energy.
So, U(initial)=U(final); m(1)gh(initial)=m(2)gh(final).
Plug in your numbers and youll get it. (.948m)
you find green bead velocity from conversation of momentum between two time befor collide & after collide so use conservation of energy
what is the m1 height?
I use U(potential energy) for both b/c when it starts at rest it obviously has no kinetic energy and it is all potential. When the green bead is at its max height, its at rest (relatively) so its energy is also all in the form of potential energy (U).
you'r right but we ought be use two conservation of energy one's for finding velocity of green &2nd for finding h of green not using one relation
Cant understand what hosein is trying to saying, but my answer is right.