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\[F=GmM/(R _{e}+r)^2\]
where M is mass of the Earth & Re is radius of the Earth

what is Gm and r?

i think hosein it is h because the question stats that is about the altitude

uhm, I don't really know the numbers to plug into the equation

yea here r is h

you can't solve this,bath?

so u can put 2000km as h or 5o as h
but u cannot solve it

ya

i don't know what m is

m is mass of 2nd body

do you know what value I would plug into it?

mass of an object e.g 40 kg
but is negligible as compared to earths mass

G=6.67*10(-11) N(m/kg)^2
M = 5.9722 × 1024 kg

subtitute the values given if u have any word problem

you ought be consider that in formula

yea put it in formula

you should these standard values in the formula

and then \[((6.67\times10^{-11}) \times 40) \div ((6.38 \times 10^{6}) + 2000)\]

where is Earth mass? and denominator has power 2

but accelaration due to gravity too comes in the formula

we forgot the main thing

what thing?sgholap100

accelaration due to gravity

ican't understand your goal?can you explane

you can use gRe^2 instead of GMe

your goal is?\[mg=GMm/R _{e}^2\]
am i right?

ithink it's right.

yes you r right

so would the answer be 391.7 ?

ok ya I think I got it, thanks guys :)