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What would be the gravitational field strength 2000km above the Earth? 50km above the Earth?
 2 years ago
 2 years ago
What would be the gravitational field strength 2000km above the Earth? 50km above the Earth?
 2 years ago
 2 years ago

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sgholap100Best ResponseYou've already chosen the best response.1
Gravity decreases with altitude, since greater altitude means greater distance from the Earth's center. so the gravity at 2000 km above the earth surface will be very less as compare to 50 km above the earth surface.
 2 years ago

hoseinBest ResponseYou've already chosen the best response.2
\[F=GmM/(R _{e}+r)^2\] where M is mass of the Earth & Re is radius of the Earth
 2 years ago

hoseinBest ResponseYou've already chosen the best response.2
r is distance of mass to Earth and G is gravitation constant that equal to 6.63*10^34(i'm not sure about G's value but i think that.many of physics book has this eg holliday)
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
G is the gravitational constant and m is the mass of any object on the earth surface it is not r it is h which means
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
i think hosein it is h because the question stats that is about the altitude
 2 years ago

beth12345Best ResponseYou've already chosen the best response.0
uhm, I don't really know the numbers to plug into the equation
 2 years ago

hoseinBest ResponseYou've already chosen the best response.2
you can't solve this,bath?
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
so u can put 2000km as h or 5o as h but u cannot solve it
 2 years ago

beth12345Best ResponseYou've already chosen the best response.0
i don't know what m is
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
m is the mass of a any object on the earth surface or the object above the earth surface e.g a satellite
 2 years ago

beth12345Best ResponseYou've already chosen the best response.0
do you know what value I would plug into it?
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
mass of an object e.g 40 kg but is negligible as compared to earths mass
 2 years ago

hoseinBest ResponseYou've already chosen the best response.2
G=6.67*10(11) N(m/kg)^2 M = 5.9722 × 1024 kg
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
subtitute the values given if u have any word problem
 2 years ago

hoseinBest ResponseYou've already chosen the best response.2
you ought be consider that in formula
 2 years ago

beth12345Best ResponseYou've already chosen the best response.0
ok so would the equation then become \[G= 6.67\times10^{11}\] \[M= 5.98 \times10^{24}\] \[R e = 6.38 \times10^{6 }\] \[h= (2000)or (50)\]
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
you should these standard values in the formula
 2 years ago

beth12345Best ResponseYou've already chosen the best response.0
and then \[((6.67\times10^{11}) \times 40) \div ((6.38 \times 10^{6}) + 2000)\]
 2 years ago

hoseinBest ResponseYou've already chosen the best response.2
where is Earth mass? and denominator has power 2
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
but accelaration due to gravity too comes in the formula
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
we forgot the main thing
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
accelaration due to gravity
 2 years ago

hoseinBest ResponseYou've already chosen the best response.2
ican't understand your goal?can you explane
 2 years ago

hoseinBest ResponseYou've already chosen the best response.2
you can use gRe^2 instead of GMe
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
as the question say that the object is above earth surface accelaration due to gravity(g=9.8m/s^2) too comes then the formula becomes
 2 years ago

hoseinBest ResponseYou've already chosen the best response.2
your goal is?\[mg=GMm/R _{e}^2\] am i right?
 2 years ago

beth12345Best ResponseYou've already chosen the best response.0
\[((6.67 \times 10 ^{11}) \times 40) \times 5.98 \times 10 ^{24}) \div(6.38 \times 10 ^{6} +2000)^{2} \]
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
oh yeah i am sorry its was my mistake i was considering Effect of altitude on gravity @hosein u r right
 2 years ago

beth12345Best ResponseYou've already chosen the best response.0
so would the answer be 391.7 ?
 2 years ago

beth12345Best ResponseYou've already chosen the best response.0
ok ya I think I got it, thanks guys :)
 2 years ago

sgholap100Best ResponseYou've already chosen the best response.1
welcome but do one thing neglect the m and h in the formula as they are very small as compared to M and R OK ^_^
 2 years ago
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