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beth12345
 4 years ago
What would be the gravitational field strength 2000km above the Earth? 50km above the Earth?
beth12345
 4 years ago
What would be the gravitational field strength 2000km above the Earth? 50km above the Earth?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Gravity decreases with altitude, since greater altitude means greater distance from the Earth's center. so the gravity at 2000 km above the earth surface will be very less as compare to 50 km above the earth surface.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[F=GmM/(R _{e}+r)^2\] where M is mass of the Earth & Re is radius of the Earth

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0r is distance of mass to Earth and G is gravitation constant that equal to 6.63*10^34(i'm not sure about G's value but i think that.many of physics book has this eg holliday)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0G is the gravitational constant and m is the mass of any object on the earth surface it is not r it is h which means

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think hosein it is h because the question stats that is about the altitude

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0uhm, I don't really know the numbers to plug into the equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can't solve this,bath?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so u can put 2000km as h or 5o as h but u cannot solve it

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0i don't know what m is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0m is mass of 2nd body

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0m is the mass of a any object on the earth surface or the object above the earth surface e.g a satellite

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0do you know what value I would plug into it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mass of an object e.g 40 kg but is negligible as compared to earths mass

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0G=6.67*10(11) N(m/kg)^2 M = 5.9722 × 1024 kg

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0subtitute the values given if u have any word problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you ought be consider that in formula

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0ok so would the equation then become \[G= 6.67\times10^{11}\] \[M= 5.98 \times10^{24}\] \[R e = 6.38 \times10^{6 }\] \[h= (2000)or (50)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea put it in formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you should these standard values in the formula

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0and then \[((6.67\times10^{11}) \times 40) \div ((6.38 \times 10^{6}) + 2000)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0where is Earth mass? and denominator has power 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but accelaration due to gravity too comes in the formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we forgot the main thing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what thing?sgholap100

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0accelaration due to gravity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ican't understand your goal?can you explane

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can use gRe^2 instead of GMe

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0as the question say that the object is above earth surface accelaration due to gravity(g=9.8m/s^2) too comes then the formula becomes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your goal is?\[mg=GMm/R _{e}^2\] am i right?

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0\[((6.67 \times 10 ^{11}) \times 40) \times 5.98 \times 10 ^{24}) \div(6.38 \times 10 ^{6} +2000)^{2} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh yeah i am sorry its was my mistake i was considering Effect of altitude on gravity @hosein u r right

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0so would the answer be 391.7 ?

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0ok ya I think I got it, thanks guys :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0welcome but do one thing neglect the m and h in the formula as they are very small as compared to M and R OK ^_^
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