Lukecrayonz
Find the nth term of the geometric sequence:
a_2 or a[2]=3, a_5 or a[5]=(3/64), n=1



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Lukecrayonz
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@satellite73

Lukecrayonz
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@bahrom7893 anything? haha

Lukecrayonz
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I literally know the equation if you have a[1], but nothing when you're solving for a[1]


Lukecrayonz
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Because the equation while using a[1], is a[n]=a[1]r^(n1)

bahrom7893
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a2=a1*r=3; a1=3/r

bahrom7893
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just do the same thing as the solved example.. or is there a trick somewhere?

Lukecrayonz
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And solving for r now.. other example doesn't make that much sense to me, and I feel like there is a trick because n1, 11=0.

Lukecrayonz
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and anything to the power of 0 is 1, so a[1]*1=a[1]..?

bahrom7893
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r is either powers of 4 or 2..

Lukecrayonz
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Hmm..?

bahrom7893
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hang on..

bahrom7893
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r=1/4, a1=3/1/4=12

bahrom7893
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a2=3=a1r
a1=3/r

bahrom7893
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a5=a1r^4=a1rr^3=3r^3=3/64

bahrom7893
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r^3=1/64
r=1/4

bahrom7893
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a1=3/r=3/1/4=12

Lukecrayonz
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Got it! Thank you so much haha, stumped me

bahrom7893
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i don't even know why they give u n, it's totally irrelevant imo

Lukecrayonz
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Got another question, that literally has nothing to do with anything..

Lukecrayonz
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Posted it