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Lukecrayonz

Find the nth term of the geometric sequence: a_2 or a[2]=3, a_5 or a[5]=(3/64), n=1

  • 2 years ago
  • 2 years ago

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  1. Lukecrayonz
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    @satellite73

    • 2 years ago
  2. Lukecrayonz
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    @bahrom7893 anything? haha

    • 2 years ago
  3. Lukecrayonz
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    I literally know the equation if you have a[1], but nothing when you're solving for a[1]

    • 2 years ago
  4. Lukecrayonz
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    http://screensnapr.com/v/3ZOlWC.png maybe this will help

    • 2 years ago
  5. Lukecrayonz
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    Because the equation while using a[1], is a[n]=a[1]r^(n-1)

    • 2 years ago
  6. bahrom7893
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    a2=a1*r=3; a1=3/r

    • 2 years ago
  7. bahrom7893
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    just do the same thing as the solved example.. or is there a trick somewhere?

    • 2 years ago
  8. Lukecrayonz
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    And solving for r now.. other example doesn't make that much sense to me, and I feel like there is a trick because n-1, 1-1=0.

    • 2 years ago
  9. Lukecrayonz
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    and anything to the power of 0 is 1, so a[1]*1=a[1]..?

    • 2 years ago
  10. bahrom7893
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    r is either powers of 4 or 2..

    • 2 years ago
  11. Lukecrayonz
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    Hmm..?

    • 2 years ago
  12. bahrom7893
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    hang on..

    • 2 years ago
  13. bahrom7893
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    r=1/4, a1=3/1/4=12

    • 2 years ago
  14. bahrom7893
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    a2=3=a1r a1=3/r

    • 2 years ago
  15. bahrom7893
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    a5=a1r^4=a1rr^3=3r^3=3/64

    • 2 years ago
  16. bahrom7893
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    r^3=1/64 r=1/4

    • 2 years ago
  17. bahrom7893
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    a1=3/r=3/1/4=12

    • 2 years ago
  18. Lukecrayonz
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    Got it! Thank you so much haha, stumped me

    • 2 years ago
  19. bahrom7893
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    i don't even know why they give u n, it's totally irrelevant imo

    • 2 years ago
  20. Lukecrayonz
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    Got another question, that literally has nothing to do with anything..

    • 2 years ago
  21. Lukecrayonz
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    Posted it

    • 2 years ago
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