Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
jadefalcon
Group Title
Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. One force is 9.0 N, acting due east, and the other is 8.0 N, acting 62° north of west. What is the magnitude of the body's acceleration?
 2 years ago
 2 years ago
jadefalcon Group Title
Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. One force is 9.0 N, acting due east, and the other is 8.0 N, acting 62° north of west. What is the magnitude of the body's acceleration?
 2 years ago
 2 years ago

This Question is Closed

Taufique Group TitleBest ResponseYou've already chosen the best response.0
dw:1332049690832:dw the net force on the body =(98sin62)i^+(8cos62)j^ Apply vector method to find the magnitude of the net force. after it find the acceleration: acceleration=(magnitude of the net force)/mass of the body.
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
angle with normal or horizontal? if horizontal:\[8\cos62+90=ma \]&\[N+8\sin62=mg\]
 2 years ago

jadefalcon Group TitleBest ResponseYou've already chosen the best response.0
yeh if finding the xcoordinate use cos from what i know
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
ordinarily angle with horizontaldw:1332050614025:dw
 2 years ago

jadefalcon Group TitleBest ResponseYou've already chosen the best response.0
i get 1.75m/s^2 but the answer is 2.9 m/s^2
 2 years ago

Taufique Group TitleBest ResponseYou've already chosen the best response.0
@hosein here Normal force will be equal to weight of the body.hence they will be cancel to each other.
 2 years ago

jadefalcon Group TitleBest ResponseYou've already chosen the best response.0
i will try use pythagoras with vector notation
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
one the force has angle so it has component throgh normal
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
my ans is same to you @jadefalcon are you sure about answer?
 2 years ago

jadefalcon Group TitleBest ResponseYou've already chosen the best response.0
straight from the book...you don't consider gravity in this problem
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
why we use gravity !we have'nt got friction here so we don't use it
 2 years ago

Taufique Group TitleBest ResponseYou've already chosen the best response.0
@hosein,yes ,you can also do here but it is not necessary here
 2 years ago

jadefalcon Group TitleBest ResponseYou've already chosen the best response.0
ah k i was just looking at your diagram...
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
so the answer is..........?
 2 years ago

jadefalcon Group TitleBest ResponseYou've already chosen the best response.0
2.9 m/s^2 and working is???
 2 years ago

jadefalcon Group TitleBest ResponseYou've already chosen the best response.0
im still fiddling with angles to come up with an answer
 2 years ago

jadefalcon Group TitleBest ResponseYou've already chosen the best response.0
ohh i see now
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
i don't understand what are you saying
 2 years ago

jadefalcon Group TitleBest ResponseYou've already chosen the best response.0
so 180deg mins 62degs =118degs so (98cos118)/3=4.25 so (98sin118)/3=1.94 squareroot(4.25^2 + 1.94^2) = wrong answer arrrgh
 2 years ago

Taufique Group TitleBest ResponseYou've already chosen the best response.0
oh sorry the diagram is wrong , see true diagram here.dw:1332051564007:dw then net force =(98cos62)i^+(8sin62)j^ then follow same way for finding the acceleration. acceleration must be 2.9m/sec^2(about)
 2 years ago

jadefalcon Group TitleBest ResponseYou've already chosen the best response.0
ahhh yes he is right...but you forgot to divide by 3 at the end
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.