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abgl20

  • 2 years ago

Determine the points of intersection of two graphs defined by y = x^2 + 1 and y = 3x + 5

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  1. emily776
    • 2 years ago
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    there are two points of intersection, (2,-1) and (4,17)...u could have just put it in the calculator!

  2. abgl20
    • 2 years ago
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    thanks, but can you kindly show me the solution?

  3. freckles
    • 2 years ago
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    I'm sorry I will should how you how to get the solution...or I will walk you through it :)

  4. freckles
    • 2 years ago
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    So we have y=x^2+1 and y=3x+5 We want to know when these are these same So we want to know when x^2+1 is the same as 3x+5 x^2+1 = 3x+5 Can you solve x^2+1=3x+5

  5. freckles
    • 2 years ago
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    \[x^2+1-3x-5=0\] \[x^2-3x-4=0\] How about this? This form should look familiar

  6. abgl20
    • 2 years ago
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    x=-1 x=4 are those right? btw, thank you for the patience, freckles..

  7. freckles
    • 2 years ago
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    (x-4)(x+1)=0 yes thats right! :)

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