Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

abgl20

  • 4 years ago

Determine the points of intersection of two graphs defined by y = x^2 + 1 and y = 3x + 5

  • This Question is Closed
  1. emily776
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    there are two points of intersection, (2,-1) and (4,17)...u could have just put it in the calculator!

  2. abgl20
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks, but can you kindly show me the solution?

  3. freckles
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I'm sorry I will should how you how to get the solution...or I will walk you through it :)

  4. freckles
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    So we have y=x^2+1 and y=3x+5 We want to know when these are these same So we want to know when x^2+1 is the same as 3x+5 x^2+1 = 3x+5 Can you solve x^2+1=3x+5

  5. freckles
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[x^2+1-3x-5=0\] \[x^2-3x-4=0\] How about this? This form should look familiar

  6. abgl20
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x=-1 x=4 are those right? btw, thank you for the patience, freckles..

  7. freckles
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    (x-4)(x+1)=0 yes thats right! :)

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy