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sri_mulyani
The surface of the water in a tank 2,5 m above its base. if there is a small hole at the base of the tank , water will flow out with velocity of???
did they give the radius of the base?
ok sorry i though this would be similar to a calc problem. if it is then i suggest using derivatives to solve the problem. are you failiar with calculus?
Hi you can use Bernloli equation between two point A & B |dw:1332158745342:dw| \[P _{0}+(1/2)\rho v^2=P _{0}+\rho gy\]we now that velocity in top of water is negligible
i was forgot : here y=2.5
|dw:1332170757662:dw| apply conservation of energy theorem: total mechanical energy at the top=total mechanical energy at the base Po(pressure energy)+0(kinetic energy)+\[\rho\]gh(potential energy)=Po(pressure energy)+1/2\[\rho\]V^2(kinetic energy)+0(potential energy)..... put the value in the above equation and get the value of V.
ok... thanks for answer..