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sri_mulyani

  • 2 years ago

The surface of the water in a tank 2,5 m above its base. if there is a small hole at the base of the tank , water will flow out with velocity of???

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  1. sheena101
    • 2 years ago
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    did they give the radius of the base?

  2. sri_mulyani
    • 2 years ago
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    no radius

  3. sheena101
    • 2 years ago
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    ok sorry i though this would be similar to a calc problem. if it is then i suggest using derivatives to solve the problem. are you failiar with calculus?

  4. hosein
    • 2 years ago
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    Hi you can use Bernloli equation between two point A & B |dw:1332158745342:dw| \[P _{0}+(1/2)\rho v^2=P _{0}+\rho gy\]we now that velocity in top of water is negligible

  5. hosein
    • 2 years ago
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    i was forgot : here y=2.5

  6. Taufique
    • 2 years ago
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    |dw:1332170757662:dw| apply conservation of energy theorem: total mechanical energy at the top=total mechanical energy at the base Po(pressure energy)+0(kinetic energy)+\[\rho\]gh(potential energy)=Po(pressure energy)+1/2\[\rho\]V^2(kinetic energy)+0(potential energy)..... put the value in the above equation and get the value of V.

  7. sri_mulyani
    • 2 years ago
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    ok... thanks for answer..

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