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That's not it!

\[\text{Hint: }a^{\phi(n)}\equiv1\text{ }(\text{mod }n)\text{, where }\gcd(a,n)=1.\]

quite tricky...:)

Is that fermat's or euler's thingy...I can't remember

glad you are back!

the last digit is 9, no?

Yes it is. :) Did you use Euler's theorem?

no I used a little logic
no idea what that theorem is

1,3,9,7,1,3,...
so 1234567890/4=308641927+2/4
and 3^2=9

29

how you got the other digit is what I want to know

I am pretty sure you can figure out what those two digits are by having told you that up there. ;)

thank you for the compliment across, it means so much knowing who it's coming from
:D

49

Very nice across :)

That is correct. :)

And if you are in a hurry, just a one liner in python: http://ideone.com/47UX7