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y2o2
 4 years ago
Solve it ... if you can :)
f(x) + f´(x) = x³ + 5x² + 2
y2o2
 4 years ago
Solve it ... if you can :) f(x) + f´(x) = x³ + 5x² + 2

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\large f(x) = x^{3}+2x^{2}4x+6+Ce^{x}\]

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.0Nope, that's not the answer , and don't try integration.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0really, oh ok i just solved it like it was a linear ODE

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0actually it is right http://www.wolframalpha.com/input/?i=y%27+%2By+%3D+x^3+%2B5x^2%2B2

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.0No , it's not . the function doesn't contain any unknown but "x".

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0? C is just a constant, you have to provide an initial value or a point to get a particular solution

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.0f(x) + f´(x) = x³ + 5x² + 2 so x³ + 5x² + 2 is the function plus its derivative so you you have to extract from x³ + 5x² + 2 a function and it's derivative x³ is the highest power , so it must belong to f(x) so f(x) = x³ +... and f´(x) = 3x²+... so f(x) = x³ + 2x²+... , so that 2x² + 3x² = 5x²+... and f´(x) = 3x² + 4x+... so f(x) = x³ + 2x²  4x+... , so that 4x+4x =0 f´(x) = 3x² + 4x4 f(x) = x³ + 2x²  4x + 6 so that 4+6 = 2 f(x) + f´(x) = (x³+2x²4x+6 )+ (3x²+4x4) = x³+5x²+2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh i see you solved it intuitively, well we are both correct if i make C=0 your answer is only 1 of many possible solutions to the differential equation
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