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Solve it ... if you can :) f(x) + f´(x) = x³ + 5x² + 2

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\[\large f(x) = x^{3}+2x^{2}-4x+6+Ce^{-x}\]
Nope, that's not the answer , and don't try integration.
really, oh ok i just solved it like it was a linear ODE

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actually it is right^3+%2B5x^2%2B2
No , it's not . the function doesn't contain any unknown but "x".
? C is just a constant, you have to provide an initial value or a point to get a particular solution
f(x) + f´(x) = x³ + 5x² + 2 so x³ + 5x² + 2 is the function plus its derivative so you you have to extract from x³ + 5x² + 2 a function and it's derivative x³ is the highest power , so it must belong to f(x) so f(x) = x³ +... and f´(x) = 3x²+... so f(x) = x³ + 2x²+... , so that 2x² + 3x² = 5x²+... and f´(x) = 3x² + 4x+... so f(x) = x³ + 2x² - 4x+... , so that -4x+4x =0 f´(x) = 3x² + 4x-4 f(x) = x³ + 2x² - 4x + 6 so that -4+6 = 2 f(x) + f´(x) = (x³+2x²-4x+6 )+ (3x²+4x-4) = x³+5x²+2
oh i see you solved it intuitively, well we are both correct if i make C=0 your answer is only 1 of many possible solutions to the differential equation
great work though :)
thank you :)

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